Given a Scanner reference variable named input that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space. Hint: Use input.nextLine() to read a line and use input.hasNextLine() to test if the input has a next line available to read.
Given a Scanner reference variable named input that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space. Hint: Use input.nextLine() to read a line and use input.hasNextLine() to test if the input has a next line available to read.
Computer Networking: A Top-Down Approach (7th Edition)
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Chapter1: Computer Networks And The Internet
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Please write in Java code
![### Reading and Printing a Sequence of Lines with a Scanner in Java
**Problem Statement:**
Given a `Scanner` reference variable named `input` that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space.
**Hint:**
- Use `input.nextLine()` to read a line.
- Use `input.hasNextLine()` to test if the input has a next line available to read.
### Sample Solution
Here is a sample solution to address the given problem:
```java
StringBuilder result = new StringBuilder();
while (input.hasNextLine()) {
String line = input.nextLine();
if (result.length() == 0) {
result.append(line); // No leading space for the first line
} else {
result.append(" ").append(line); // Space before subsequent lines
}
}
System.out.println(result.toString());
```
### Explanation:
1. **StringBuilder Initialization:**
- We initialize a `StringBuilder` named `result` to efficiently concatenate strings.
2. **While Loop with `input.hasNextLine()`:**
- We use a `while` loop that continues as long as there is another line to read (`input.hasNextLine()` returns `true`).
3. **Reading and Appending Lines:**
- Inside the loop, `input.nextLine()` reads the current line.
- If `result` is empty (for the first iteration), append the line without a leading space.
- For subsequent lines, append a space before appending the line to ensure they are separated by a space.
4. **Printing the Result:**
- Finally, we print the concatenated result using `System.out.println(result.toString())`.
This solution ensures that all the lines are read and printed on a single line, separated by spaces, effectively solving the given task using the Java `Scanner` class.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6a7d46e-c507-421a-9895-6bbf67ae6667%2Fa4b35b6d-9ed1-4d18-9879-82bb0932a03f%2Fw2up4u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reading and Printing a Sequence of Lines with a Scanner in Java
**Problem Statement:**
Given a `Scanner` reference variable named `input` that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space.
**Hint:**
- Use `input.nextLine()` to read a line.
- Use `input.hasNextLine()` to test if the input has a next line available to read.
### Sample Solution
Here is a sample solution to address the given problem:
```java
StringBuilder result = new StringBuilder();
while (input.hasNextLine()) {
String line = input.nextLine();
if (result.length() == 0) {
result.append(line); // No leading space for the first line
} else {
result.append(" ").append(line); // Space before subsequent lines
}
}
System.out.println(result.toString());
```
### Explanation:
1. **StringBuilder Initialization:**
- We initialize a `StringBuilder` named `result` to efficiently concatenate strings.
2. **While Loop with `input.hasNextLine()`:**
- We use a `while` loop that continues as long as there is another line to read (`input.hasNextLine()` returns `true`).
3. **Reading and Appending Lines:**
- Inside the loop, `input.nextLine()` reads the current line.
- If `result` is empty (for the first iteration), append the line without a leading space.
- For subsequent lines, append a space before appending the line to ensure they are separated by a space.
4. **Printing the Result:**
- Finally, we print the concatenated result using `System.out.println(result.toString())`.
This solution ensures that all the lines are read and printed on a single line, separated by spaces, effectively solving the given task using the Java `Scanner` class.
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