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Given a Scanner reference variable named input that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space. Hint: Use input.nextLine() to read a line and use input.hasNextLine() to test if the input has a next line available to read.

Given a Scanner reference variable named input that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space. Hint: Use input.nextLine() to read a line and use input.hasNextLine() to test if the input has a next line available to read.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Please write in Java code

### Reading and Printing a Sequence of Lines with a Scanner in Java **Problem Statement:** Given a `Scanner` reference variable named `input` that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space. **Hint:** - Use `input.nextLine()` to read a line. - Use `input.hasNextLine()` to test if the input has a next line available to read. ### Sample Solution Here is a sample solution to address the given problem: ```java StringBuilder result = new StringBuilder(); while (input.hasNextLine()) { String line = input.nextLine(); if (result.length() == 0) { result.append(line); // No leading space for the first line } else { result.append(" ").append(line); // Space before subsequent lines } } System.out.println(result.toString()); ``` ### Explanation: 1. **StringBuilder Initialization:** - We initialize a `StringBuilder` named `result` to efficiently concatenate strings. 2. **While Loop with `input.hasNextLine()`:** - We use a `while` loop that continues as long as there is another line to read (`input.hasNextLine()` returns `true`). 3. **Reading and Appending Lines:** - Inside the loop, `input.nextLine()` reads the current line. - If `result` is empty (for the first iteration), append the line without a leading space. - For subsequent lines, append a space before appending the line to ensure they are separated by a space. 4. **Printing the Result:** - Finally, we print the concatenated result using `System.out.println(result.toString())`. This solution ensures that all the lines are read and printed on a single line, separated by spaces, effectively solving the given task using the Java `Scanner` class.
Transcribed Image Text:### Reading and Printing a Sequence of Lines with a Scanner in Java **Problem Statement:** Given a `Scanner` reference variable named `input` that has been associated with an input source consisting of a sequence of lines, write the code necessary to read in every line and print them all out on a single line, separated by a space. **Hint:** - Use `input.nextLine()` to read a line. - Use `input.hasNextLine()` to test if the input has a next line available to read. ### Sample Solution Here is a sample solution to address the given problem: ```java StringBuilder result = new StringBuilder(); while (input.hasNextLine()) { String line = input.nextLine(); if (result.length() == 0) { result.append(line); // No leading space for the first line } else { result.append(" ").append(line); // Space before subsequent lines } } System.out.println(result.toString()); ``` ### Explanation: 1. **StringBuilder Initialization:** - We initialize a `StringBuilder` named `result` to efficiently concatenate strings. 2. **While Loop with `input.hasNextLine()`:** - We use a `while` loop that continues as long as there is another line to read (`input.hasNextLine()` returns `true`). 3. **Reading and Appending Lines:** - Inside the loop, `input.nextLine()` reads the current line. - If `result` is empty (for the first iteration), append the line without a leading space. - For subsequent lines, append a space before appending the line to ensure they are separated by a space. 4. **Printing the Result:** - Finally, we print the concatenated result using `System.out.println(result.toString())`. This solution ensures that all the lines are read and printed on a single line, separated by spaces, effectively solving the given task using the Java `Scanner` class.
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