Given a regression model with theta0 = 67.4 and theta1 = 18.28, find the estimated y value for x = 16. (Use 4 significant figures)
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Given a regression model with theta0 = 67.4 and theta1 = 18.28, find the estimated y value for x = 16. (Use 4 significant figures)
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- A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.145 b=20.742 r?=0.508369 r=-0.713 Use this to predict the number of situps a person who watches 2.5 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.226 b=33.622 r²-0.4489 r=-0.67 Use this to predict the number of situps a person who watches 3 hours of TV can do (to one decimal place)A regression analysis was performed to determine if there is a relationship between hours of TV watched per day (xx) and number of sit ups a person can do (yy). The results of the regression were: y=ax+b a=-1.152 b=30.418 r2=0.703921 r=-0.839 1. Use this to predict the number of sit ups a person who watches 2.5 hours of TV can do, and please round your answer to a whole number
- A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: ý = bo + bịx bo = 36.465 - 1.082 b1 - 0.646 Use this to predict the number of situps a person who watches 2.5 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-0.649 b=20.136 r2=0.488601 r=-0.699 Use this to predict the number of situps a person who watches 2.5 hours of TV can do (to one decimal place)Draw the regression line for the following equation: Y = -3 + (1) X Show your calculation for a low and high value on the predictor value.
- A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were: y=ax+b a=-0.609 b=27.646 r2=0.910116 r=-0.954 Use this to predict the number of situps a person who watches 12 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-0.649 b=20.136 r2=0.488601 r=-0.699 Use this to predict the number of situps a person who watches 2.5 hours of TV can do (to one decimal place)Use the regression equation, Ŷ = 3X + 4, to find the predicted Y value corresponding to X = 2 The predicted Y value = ?
- A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: ŷ=ax+b a=-1.312 b=36.478 r²-0.363609 r=-0.603 Use this to predict the number of situps a person who watches 9.5 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.091 b=30.228 r2=0.698896 r=-0.836 Use this to predict the number of situps a person who watches 3.5 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.371 b=36.465 ²0.395641 r=-0.629 Use this to predict the number of situps a person who watches 9 hours of TV can do (to one decimal place)
