Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows: print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence:

  • If n is even, divide it by 2
  • If n is odd, multiply it by 3 and add 1 (i.e. 3n +1)
  • Continue until n is 1

Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line.

The output format can be achieved as follows:
print(n, end='\t')

Ex: If the input is:

25

the output is:

25 76 38 19 58 29 88 44 22 11

34 17 52 26 13 40 20 10 5 16

8 4 2 1

 

this is what i have

 

n = int(input())
count = 1
while n != 1:
    if count%10==0:
        print(n,'\t')
    else:
        print(n, end='\t')
    if n%2==0:
        n = int(n/2)
    else:
        n = int(n*3 + 1)
    count = count + 1

print(n)
   

the output is correct but theres  whitespaces that arnt needed

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