Given a normal distribution with a mean of 150, and a standard deviation of 7.5, find the value of a normal variable X whose corresponding standard score is z = -2.5. Note: Write the exact answer in the space provided.
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- Suppose X ~ N(19, 3). Between what x values does 68.27% of the data lie? The range of x values is centered at the mean of the distribution (i.e., 19).The sample mean is x ~ 93.3. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that o = 12.5. The mean glucose level for horses should be M = 85 mg/100 ml.+ Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use a = 0.05.Suppose that an accounting firm does a study to determine the time needed to complete one person's tax forms. It randomly surveys 200 people. The sample mean is 22.3 hours. There is a known population standard deviation of 7.0 hours. The population distribution is assumed to be normal. Which distribution should you use for this problem? (Round your answers to two decimal places.) X ~ ,
- A normal-shaped distribution with mean of 40 and standard deviation of 8 is transformed into z-scores. Describe the shape, the mean, and the standard deviation for the resulting distribution of z-scores.A population of values has a normal distribution with �=196.2 and �=85. You intend to draw a random sample of size �=197.Find P73, which is the score separating the bottom 73% scores from the top 27% scores.P73 (for single values) = Find P73, which is the mean separating the bottom 73% means from the top 27% means.P73 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Given X~N(50,10) What are the value of the mean and standard deviation. What value of x has a z-score of 1.4? What is the z-score that corresponds to x=30
- The mean serum cholesterol level of a large population of overwieght children is 220 milligrams per deciliter (mg/dl), and the standard deviation is 16.3 mg/dl. If a random sample of 35 overwieght children is selected, find the probability that the mean will be between 220 and 222 mg/dl. Assume the serume cholesterol level variable is normolly distributed. Explain?Jerome averages 16 points a game with a standard deviation of four points. X ~ N(16,4). Suppose Jerome scores ten points in a game. The z-score when x = 10 is –1.5. This score tells you that x = 10 is standard deviations to the _(right or left) of the mean _(What is the mean?).Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken nine blood tests for uric acid. The mean concentration was x = 5.33 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with ? = 1.79 mg/dl. (a)Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit=__ upper limit=__ margin of error=__ (b)What conditions are necessary for your calculations? (Select all that apply.) A-? is known B-? is unknown C-uniform distribution of uric acid D-n is large E-normal distribution of uric acid c)Interpret your results in the context of this problem. MULTIPLE CHOICE A-We are 5% confident that the true uric acid level for this patient falls within this interval.…
- Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken five blood tests for uric acid. The mean concentration was x = 5.29 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with ? = 1.93 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.)lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) normal distribution of uric acid n is large ? is known uniform distribution of uric acid ? is unknown c) Find the sample size necessary for a 95% confidence level with maximal margin of error E = 1.10 for the mean concentration of uric acid in this patient's blood. (Round your answer up to the…A normal shaped distribution with mean of 40 and standard deviation of 8 is transformed into z-score. Describe the shape, the mean, and the standard deviation for the resulting distribution of z-score.During the first day of classes for the second semester, the Statistics and Probability teacher of your class conducted a test to a random sample of 100 students. They got a mean score of 80.68 with a population standard deviation of 12. The population mean is 78.37. Use 0.05 level of significance. Find the Z-value.