Given a matrix A = PDP-¹ with [1 2] 5 3 Р = P= then find all matrices P and D below that also satisfy that A = PDP-1 Note: Choose all the correct answers. -1 4] -5 6 -1 41 -5 6 2 Р P = [10 -21 -3 and D= and Ď and D= [2 07 D = [²3], 0 and Ď Ď= 2 03 [30] 02 [30] 02
Given a matrix A = PDP-¹ with [1 2] 5 3 Р = P= then find all matrices P and D below that also satisfy that A = PDP-1 Note: Choose all the correct answers. -1 4] -5 6 -1 41 -5 6 2 Р P = [10 -21 -3 and D= and Ď and D= [2 07 D = [²3], 0 and Ď Ď= 2 03 [30] 02 [30] 02
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Given a matrix A = PDP-¹ with
(3)
[1 2]
5 3
P = [ -= 13
then find all matrices P and D below that also satisfy that A = PDP-1
Note: Choose all the correct answers.
-1 41
P = [13]
Р
-5 6
P = 10
P =
P =
-1 4]
-5 6
||
2 -21
-
-3
[2
P=
=
ܥ ܘ
[4 3
6 15
3 5
and D=
and Ď=
=
and Ď=
and Ď
and D-
Ď=
2 0
03
and Ď Ď= - [8
[30]
0 2
3 0
02
-13
[2 01
0 3
2 0
[1391]
[2 07
0
0 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf4e9f68-b5eb-4a27-ae76-fd0a8c3d58af%2Fada26b80-f4cd-48c3-8a6c-2f3556a3856a%2Fxr795yp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given a matrix A = PDP-¹ with
(3)
[1 2]
5 3
P = [ -= 13
then find all matrices P and D below that also satisfy that A = PDP-1
Note: Choose all the correct answers.
-1 41
P = [13]
Р
-5 6
P = 10
P =
P =
-1 4]
-5 6
||
2 -21
-
-3
[2
P=
=
ܥ ܘ
[4 3
6 15
3 5
and D=
and Ď=
=
and Ď=
and Ď
and D-
Ď=
2 0
03
and Ď Ď= - [8
[30]
0 2
3 0
02
-13
[2 01
0 3
2 0
[1391]
[2 07
0
0 3
![0 [2 1]
3 5
P-B
P =
4 37
P-5
P =
6 15
P=
and Ď=
2 -2]
10 -3
and Ď=
[3 01
0 2
[30]
0 2
and Ď=
[2 0]
3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf4e9f68-b5eb-4a27-ae76-fd0a8c3d58af%2Fada26b80-f4cd-48c3-8a6c-2f3556a3856a%2Fof5vnyo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:0 [2 1]
3 5
P-B
P =
4 37
P-5
P =
6 15
P=
and Ď=
2 -2]
10 -3
and Ď=
[3 01
0 2
[30]
0 2
and Ď=
[2 0]
3
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