Given a map that indicates that 1 inch on the map corresponds to 2000 ft in real life, we've come up with an equation that states "real life size = 24000 in. (distance on map)". A follow up question says there is a 50 ft boat on the river of the map. Use your equation to find out how big that boat would be on the satellite photo. The solution given says that the 50 ft boat is equivalent to 4.16 inches. Where does this number come from? Using this number in place of "real life size" says the end result is 0.00208 ft, but where does the 4.16 come from??
Given a map that indicates that 1 inch on the map corresponds to 2000 ft in real life, we've come up with an equation that states "real life size = 24000 in. (distance on map)". A follow up question says there is a 50 ft boat on the river of the map. Use your equation to find out how big that boat would be on the satellite photo. The solution given says that the 50 ft boat is equivalent to 4.16 inches. Where does this number come from? Using this number in place of "real life size" says the end result is 0.00208 ft, but where does the 4.16 come from??
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Given a map that indicates that 1 inch on the map corresponds to 2000 ft in real life, we've come up with an equation that states "real life size = 24000 in. (distance on map)".
A follow up question says there is a 50 ft boat on the river of the map. Use your equation to find out how big that boat would be on the satellite photo. The solution given says that the 50 ft boat is equivalent to 4.16 inches. Where does this number come from?
Using this number in place of "real life size" says the end result is 0.00208 ft, but where does the 4.16 come from??
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