Given a main() that reads user IDs (until -1), complete the Quicksort() and Partition() functions to sort the IDs in ascending order using the Quicksort algorithm, and output the sorted IDs one per line. Ex. If the input is: kaylasimms julia myron1994 kaylajones -1 the output is: julia kaylajones kaylasimms myron1994
Given a main() that reads user IDs (until -1), complete the Quicksort() and Partition() functions to sort the IDs in ascending order using the Quicksort algorithm, and output the sorted IDs one per line. Ex. If the input is: kaylasimms julia myron1994 kaylajones -1 the output is: julia kaylajones kaylasimms myron1994
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:Given a main() that reads user IDs (until -1), complete the Quicksort() and Partition() functions to sort the IDs in ascending order using the
Quicksort algorithm, and output the sorted IDs one per line.
Ex. If the input is:
kaylasimms
julia
myron1994
kaylajones
-1
the output is:
julia
kaylajones
kaylasimms
myron1994

Transcribed Image Text:1 # include <string>
2 #include <vector>
3 #include <iostream>
4
5 using namespace std;
6
7 // TODO: Write the partitioning algorithm - pick the middle element as the
8 //
9 //
10 //
11 int Partition (vector<string> &userIDs, int i, int k) {
12
13}
14
15 // TODO: Write the quicksort algorithm that recursively sorts the Low and
16 //
high partitions
17 void Quicksort (vector<string> &userIDs, int i, int k) {
18
pivot, compare the values using two index variables L and h (Low and high),
initialized to the left and right sides of the current elements being sorted,
and determine if a swap is necessary
19}
20
21 int main() {
22 vector<string> userIDList;
23
string userID;
24
25
cin >> userID;
26
while (userID != "-1") {
27
28
29
30
31
}
// Initial call to quicksort
32 Quicksort (userIDList, 0, userIDList.size() - 1);
mm m
userIDList.push_back(userID);
cin >> userID;
33
34 for (size_t i = 0; i < userIDList.size(); ++i) {
35
cout << userIDList.at (i) << endl;;
36 }
37
38
39}
mmmm
return 0;
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