Given a block of mass 5.00 kg on a table being pulled horizontally by a rope. The rope pulls to the left with a force of 25.0 N. Which of these expressions would yield the acceleration of the block in SI units? A. 25 X 5 B. 5 divided by 5 C. 25 X 5^2 D. 25 divided by 5 E. zero
Given a block of mass 5.00 kg on a table being pulled horizontally by a rope. The rope pulls to the left with a force of 25.0 N. Which of these expressions would yield the acceleration of the block in SI units? A. 25 X 5 B. 5 divided by 5 C. 25 X 5^2 D. 25 divided by 5 E. zero
Related questions
Question
Given a block of mass 5.00 kg on a table being pulled horizontally by a rope. The rope pulls to the left with a force of 25.0 N. Which of these expressions would yield the acceleration of the block in SI units?
A. 25 X 5
B. 5 divided by 5
C. 25 X 5^2
D. 25 divided by 5
E. zero
Expert Solution
Step 1
Let F be defined as the force, m be defined as the mass of the block, and a be defined as the acceleration. Therefore,
From Newton’s second law of motion,
Step by step
Solved in 2 steps