Given a block of mass 5.00 kg on a table being pulled horizontally by a rope. The rope pulls to the left with a force of 25.0 N. Which of these expressions would yield the acceleration of the block in SI units? A. 25 X 5 B. 5 divided by 5  C. 25 X 5^2 D. 25 divided by 5  E. zero

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Given a block of mass 5.00 kg on a table being pulled horizontally by a rope. The rope pulls to the left with a force of 25.0 N. Which of these expressions would yield the acceleration of the block in SI units?

A. 25 X 5

B. 5 divided by 5 

C. 25 X 5^2

D. 25 divided by 5 

E. zero

Expert Solution
Step 1

Let F be defined as the force, m be defined as the mass of the block, and a be defined as the acceleration. Therefore,

From Newton’s second law of motion,

F=maa=Fm

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