Given a barometric pressure of 762.4 mmHg, calculate the pres- sure of each gas sample as indicated by the manometer. Atmospheric Atmospheric pressure pressure cm cm h Mercury Mercury (a) (b)
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- Calculate the time in hours it will take to evaporate a 10 mm unknown liquid at 25°C (density= 40 lb/ft³ MW= 60) in a 5 m diameter circular tank. The vapor pressure at 25°C is 180 mmHg, pressure is atmospheric and D, = 0.0329 ft²/hr. Stagnant air film is 3 mm.(1) Hydrostatic balance states Op Əz Equation -1 where p is pressure, z is altitude, p is density and g is the acceleration due to gravity. It can be shown that the reciprocal of hydrostatic balance also applies. That is Equation -2 дz Әр = -Pg, = 1 pg Use the ideal gas law (p = pRT, where R is the gas constant for dry air and Tis temperature) to eliminate p from (2). (2) Under geostrophic balance, the following balance is approximately satisfied Equation -3 fu=-g ¹ (3) where f is the Coriolis parameter, u is the zonal wind, y is meridional distance and z is altitude. (Note that the derivative on the right hand side is taken at constant pressure.) Differentiate (3) with respect to p, and use your expression from part 1 to obtain an expression relating du/ap and T/ay. This expression is called "thermal wind balance".At the top of the Blue Ridge parkway nearby (assume 4000ft above sea level), what is air pressure if sea level pressure is1.01e5 Pa. Asssume T=20C.
- The energy released from condensation in thunderstorms can be very large. Calculate the energy released into the atmosphere for a small storm of radius 1 km, assuming that 1.0 cm of rain is precipitated uniformly over this area.In a hurricane, the mean sustained wind velocity v (in meters per second) can be modeled by v(p) = 6.31013-p, where p is the air pressure in millibars at the center of the hurricane. Estimate the air pressure, p, at the center of the hurrican when the mean sustained wind velocity, (v(p)), is 60 meters per second. Round to the nearest hundredth. mbar Blank 1:(a) What is the vapor pressure of water at 20.0ºC ? (b)What percentage of atmospheric pressure does thiscorrespond to? (c) What percent of 20.0ºC air is water vapor if it has 100% relative humidity? (The density of dry air at 20.0ºC is 1.20 kg/m3 .)
- At an altitude of 1,600m, the atmospheric pressure is 81.49kPa. What is the specific humidity and relative humidity at this altitude when the dry and wet bulb temperatures are measured to be 10°C and 5°C respectively? Note, due to the low atmospheric pressure at 1,600m, the latm psychrometric chart is not valid for this problem. You will receive no points if you use itDetermine at what altitude in meters the air pressure is twice less than on the sea level using the barometic equation that is pressure as a function of height. Given that the temperature is 288.15 K. P=P0e -Mgh/RT, where Po is the pressure at sea level, M is the molar mass of air (in kg/mol), T is standard temperature, R is universal gas constant (8.314 N.m/mol K).how to solve for the density of air? can anyone explain the process and how to get the value of Rspecific gas constant (1716 ft.lbf/slug.R)? I'm really confused. Thank you
- b)Air density at 0° C and 1 atmosphere pressure is 1.3 kg / m3. Its density reaches 65 kg / m3 at 0 ° C temperature and 50 atm pressure. What does this incident explain? Where do we take advantage of this feature?Please asap(1) Hydrostatic balance states Әр Equation -1 -Pg, where p is pressure, z is altitude, pis density and g is the acceleration due to gravity. It can be shown that the reciprocal of hydrostatic balance also applies. That is Equation -2 Əz Əz Әр 1 pg Use the ideal gas law (p = pRT, where R is the gas constant for dry air and T is temperature) to eliminate p from (2). (2) Under geostrophic balance, the following balance is approximately satisfied Equation -3 fu = -g (³3), ду where f is the Coriolis parameter, u is the zonal wind, y is meridional distance and z is altitude. (Note that the derivative on the right hand side is taken at constant pressure.) Differentiate (3) with respect to p, and use your expression from part 1 to obtain an expression relating du/ap and OT/oy. This expression is called "thermal wind balance".