Given: A 25-kg block is subjected to the force F=100 N. The F= 100 N F= 100 N spring has a stiffness of k = 200 N/m and is unstretched 200 N/m 0.3 m when the block is at A. The contact surface is smooth. Find: Draw the free-body and kinetic diagrams of the block when s-0.4 m. Plan: 1) Define an inertial coordinate system. 2) Draw the block's free-body diagram, showing all external forces. 3) Draw the block's kinetic diagram, showing the inertial force vector in the proper direction.
Given: A 25-kg block is subjected to the force F=100 N. The F= 100 N F= 100 N spring has a stiffness of k = 200 N/m and is unstretched 200 N/m 0.3 m when the block is at A. The contact surface is smooth. Find: Draw the free-body and kinetic diagrams of the block when s-0.4 m. Plan: 1) Define an inertial coordinate system. 2) Draw the block's free-body diagram, showing all external forces. 3) Draw the block's kinetic diagram, showing the inertial force vector in the proper direction.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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eep moving to the right, since the net force to
the right is 68N >0.
The acceleration could be directed to the right if the block is
speeding up or to the left if it is slowing down.
- Is the block accelerating or decelerating?
“Homework”: - What is the equation for Fx(s)?
- What is the maximum distance, smax?

Transcribed Image Text:EXAMPLE
Given: A 25-kg block is subjected to
F= 100 N
F= 100 N
the force F=100 N. The
spring has a stiffness of k=
200 N/m and is unstretched
200 N/m
0.3 m
when the block is at A. The
contact surface is smooth.
Find: Draw the free-body and kinetic diagrams of the block
when s-0.4 m.
Plan: 1) Define an inertial coordinate system.
2) Draw the block's free-body diagram, showing all
external forces.
3) Draw the block's kinetic diagram, showing the inertial
force vector in the proper
direction.
ALWAYS LEARNING Dynamics, Fourteenth Edition
R.C. Hibbeler
Copyright ©2016 by Pearson Education, Inc. PEARSON
All rights reserved.

Transcribed Image Text:CD Page view
AN Read aloud
The normal force Fn is perpendicular to the contact surface.
There is no friction force since the contact surface is smooth.
When s = 0.4m, the spring's extended length is 0.5m
→4= (0,5 - 0.3)m = 0.2 m → Fs = 200N/m * 0.2m = 40N
W = 245N
How do we determine the resulting
force(s) on the block?
y
F=100 (N)
EFx = F – Fs*4/5 = (100-32)N= 68N
F- 200 A (N)
Fn
40 (N)
£Fy = 0! → Fn (vertical equilibrium)
Fn = W+ Fs*3/5 = (245+24)N = 269N
ALWAYS LEARNING Dynamics, Fourteenth Edition
R.C. Hibbeler
Copyright ©2016 by Pearson Education, Inc. PEARSON
All rights reserved.
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