Given a = -0.05, X X0.025 = 35.479, s = 207.36, and n = 22 compute the lower bound for a 95% confidence interval using the formula LB s- (n − 1) X²₁ (Round the answer to 2 decimal places.) Question Help: Video Written Example Message instructor Post to forum Submit Question Jump to Answer
Given a = -0.05, X X0.025 = 35.479, s = 207.36, and n = 22 compute the lower bound for a 95% confidence interval using the formula LB s- (n − 1) X²₁ (Round the answer to 2 decimal places.) Question Help: Video Written Example Message instructor Post to forum Submit Question Jump to Answer
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Compute the lower bound
![Given \(\alpha = 0.05\), \(\chi^2_{\frac{\alpha}{2}} = \chi^2_{0.025} = 35.479\), \(s^2 = 207.36\), and \(n = 22\), compute the lower bound for a 95% confidence interval using the formula:
\[
LB = \frac{s^2(n - 1)}{\chi^2_{\frac{\alpha}{2}}}
\]
(Round the answer to 2 decimal places.)
---
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Transcribed Image Text:Given \(\alpha = 0.05\), \(\chi^2_{\frac{\alpha}{2}} = \chi^2_{0.025} = 35.479\), \(s^2 = 207.36\), and \(n = 22\), compute the lower bound for a 95% confidence interval using the formula:
\[
LB = \frac{s^2(n - 1)}{\chi^2_{\frac{\alpha}{2}}}
\]
(Round the answer to 2 decimal places.)
---
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