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Given: 6x³2x²+3 dx. Using integration by parts (udv Svdu) and dv = uv - letting u= f(x), dv= 3 g(x) dx, find h(x) if [vdu=h(x) + C. A 6e**+3 B C D E 3e+2+6 e3 2ex²+3 3e-3x² none of the choices

Given: 6x³2x²+3 dx. Using integration by parts (udv Svdu) and dv = uv - letting u= f(x), dv= 3 g(x) dx, find h(x) if [vdu=h(x) + C. A 6e**+3 B C D E 3e+2+6 e3 2ex²+3 3e-3x² none of the choices

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given: 6x³2x²+3 dx. Using integration by parts (Sudv dv = uv - letting u= f(x), dv= 3 g(x) dx, find h(x) if ſvdu= h(x) + C. A 6ex+3 3e+² +6 e3 2ex²+3 3e-3ex² none of the choices Svdu) and B с D E
Transcribed Image Text:Given: 6x³2x²+3 dx. Using integration by parts (Sudv dv = uv - letting u= f(x), dv= 3 g(x) dx, find h(x) if ſvdu= h(x) + C. A 6ex+3 3e+² +6 e3 2ex²+3 3e-3ex² none of the choices Svdu) and B с D E
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