Given = 3.0 M Ca(oH)2 & 2.5LLooking For =g CacoH)2M × L = (3.0m)25L)mol= 7.5 mol CaoH )zM= molmol =Calx40.08 = 40.080 I x16.0 0 = ll6-0 0I x 1.0 1 1.057.09 g/mol CacoH)27.5 mol CaloH)z 57.09gCa(ott)[428.189I mol CaloH) zCaOH2The student got the answer wrong. Identify the error, explain the mistake in detailand fix it by providing the correct answer.

Answered: Image /qna-images/answer/f4077037-3208-4e48-b7cd-997f1ef0fd2b.jpg

Given = 3.0 M Ca(oH)2 & 2.5L Looking For = g CacOH)z mol = M x L = (3.0MX25 L) mol= 7,5 mol Cal0H )2 M= mol Calx40.08 = 40.08 1 x16.00 = 116 -DO | x 1.01 1. 57.09 g/mol CacoH)2 7.5 mol Ca(oH)z 57.09g Ca(ott)z= 428.18g I mol Ca(oH) 2 CaOH Y2 The student got the answer wrong. Identify the error, explain the mistake in detail and fix it by providing the correct answer.

Given = 3.0 M Ca(oH)2 & 2.5L Looking For = g CacOH)z mol = M x L = (3.0MX25 L) mol= 7,5 mol Cal0H )2 M= mol Calx40.08 = 40.08 1 x16.00 = 116 -DO | x 1.01 1. 57.09 g/mol CacoH)2 7.5 mol Ca(oH)z 57.09g Ca(ott)z= 428.18g I mol Ca(oH) 2 CaOH Y2 The student got the answer wrong. Identify the error, explain the mistake in detail and fix it by providing the correct answer.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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