Given :           (1) 2NF3 + 2NO  → N2F4  + 2ONF     ∆H= -82.9 kJ           (2) NO + ½ F2  → ONF                       ∆H = -156.9 kJ           (3) Cu + F2  → CuF2                           ∆ H= -531.0 kJ       Calculate the value of ∆H for the reaction:            2NF3 + Cu → N2F4    +  CuF2             ∆H = ? Select one: a. -400.1 KJ b. -200.1 kJ c. -100.1 kJ d. -300.1 Kj

Q: Calculate ∆fH° for sulfur dioxide given the two thermochemical equations below. Write the answer…

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Q: Calculate the ∆Hof of C6H12O6(s) from the following data:  ∆H combustion of C6H12O6(s) =…

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Q: H

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Q: Using the equations N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6 kJ/mol N₂ (g) + 3 H₂ (g) → 2 NH₃…

A: Given that, the equations are as follows --- N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6 kJ/mol N₂ (g) +…

Q: Why is it often more convenient to measure ∆H than ∆E?

A: ∆H is equal to heat change at constant pressure and ∆E is equal to heat change at constant volume.…

Q: Find the heat of reaction and explain what happen to it. Calculate the ∆H of reaction for: C3H8 (g)…

A: Solution - C3H8 (g) + 5O2 (g) →→ 3CO2 (g) + 4H2O (l)      ∆H∘rxn =∑∆H°f,products-∑∆H°f,reactants…

Q: A reaction of decomposition of a compound AB is  accompanied by absorption of some heat energy. What…

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Q: Find the heat of reaction and explain what happen to it. Calculate the ∆H of reaction for: C3H8 (g)…

A: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (l)      ∆Hrxn° = ∑∆H°f,products-∑∆H°f,reactants   ∆Hrxn° = 3 x…

Q: Consider the following generic reaction: A+2B→C+3DA+2B→C+3D, with ΔHΔH = 125 kJkJ . Determine the…

A: Here we use the concept of chemical reaction and value of delta H.

Q: Calculate ∆Gº for the reaction, 2C2H6(g)+5O2(g)→4CO(g)+6H2O(g), given ∆Gºf for C2H6(g)=-32.9 kJ/mol,…

A: 2C2H6(g)  +  5O2(g)  →  4CO(g)  +  6H2O(g) ∆Gºf for C2H6(g)=-32.9 kJ/mol, ∆Gºf for CO(g)=-137.2…

Q: What is the expected major product of the reaction shown? N-Br , light

A: We have given the organic reaction and we have to find the major product of the reaction.

Q: Determine ∆S for the phase change of 1.10 moles of water from solid to liquid at 0°C. (∆H = 6.01…

A: Entropy change of the system can be determined by knowing the values of heat change and the…

Q: Find the ∆H for the reaction below, given the following reactions and subsequent ∆H values: H2SO4…

A: The given equations are:  H2Sg + 2O2g → H2SO4l                  ∆H = -235.5 kJ  ……1 H2Sg + 2O2g →…

Q: thermochemical equation

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Q: Using the equations N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H° = -91.8 kJ/mol C(s) + 2 H₂ (g) → CH₄ (g) ∆H° =…

A: Answer:- This question is answered by using the simple concept of Hess Law of constant heat…

Q: CH4(g) + 2 Cl2(g) → CH2Cl2(g) + 2 HCl(g) Calculate ∆Hrxn° using the following data: CH3Cl(g) +…

A: Using Hess's law  Enthalpy of reaction is same for a reaction if the reaction is completes in…

Q: Find the ∆H for the reaction below, given the following reactions and subsequent ∆H values: H2SO4…

A: Thermodynamics is branch of chemistry in which we deal with amount of heat absorbed or evolved…

Q: What is the correct statement about the reaction? (At 298K, ∆H°f for CF4(g) is –933 kJ) ½…

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Q: Calculate the ∆H for the reaction: N2O4 + CO → N2O + CO2

A: Given that -  Following Reaction -  N2O4 + CO → N2O + CO2  After balancing it can be written as -…

Q: Using the equations N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6 kJ/mol N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H°…

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Q: Calculate the ∆H for the reaction  NO(g)   + O(g)   →   NO2(g) given the following information…

A: Given : Consider,  1) NO(g) + O3(g) → NO2(g) + O2(g)             ∆H1 = - 198.9 kJ 2) O3(g) → 3/2…

Q: Calculate ∆Go at 25 ᴼC for the reaction of which ∆Ho = +210kJ; ∆So = 32.5 J/K

A: Given, ∆H° = +210 KJ  ∆S° = 32.5 J/K

Q: Determine ∆S for the phase change of 2.42 moles of water from liquid to solid at 0.0 °C. (∆H = -6.01…

A: Given, ∆H = -6.01 kJ/mol T = 0°C = 273+0 K = 273 K Moles = 2.42

Q: Calculate ΔH for the following reaction: PCl3 (l) +  Cl2 (g)  → PCl5 (s) given the following: 1)…

A: Reverse of first reaction and and it will second equation and divide by 2 equation so we can that…

Q: Determine ∆S for the phase change of 1.25 moles of naphthalene from solid to liquid at 80.3°C. (∆H =…

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Q: Using the equations N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6 kJ/mol N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H°…

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Q: 4 NH3 (g)   +   5 O2 (g)      4 NO (g)   +   6 H2O (g)                       ∆H  =  -905 J   What…

A: If Equation is multiplied by 3 the Change in energy will also be three times.

Q: Determine ∆S for the phase change of 4.65 moles of water from solid to liquid at 0.0 °C. (∆H = 6.01…

A: According to the question, The moles of water is given by = 4.65 molesThe ∆H is given by = 6.01…

Q: For ionization energy, when is it more unfavorable? How does this relate to the ∆H ?

A: Unfavourable ionization energy means greater amount of energy requirements.  This is possible due to…

Q: Draw a (hess diagram) enthalpy diagram to calculate the ∆Hfc2 H5 OH using the following date ∆Hcc =…

A: Hess's law is an important rule in thermodynamics. It states that the heat absorbed by or escaped…

Q: Determine ∆S for the phase change of 2.59 moles of water from liquid to solid at 0.0 °C. (∆H = -6.01…

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Q: Given: 2C(s) + O₂(g) → 2CO(g) ∆H = -218 kJ C(s) + O₂(g) → CO₂(g) ∆H = -393 kJ How much energy is…

A: The given reactions are: 2C(s) + O₂(g) → 2CO(g)           ∆H = -218 kJ  C(s) + O₂(g) → CO₂(g)…

Q: 6. Given the following enthalpies of reaction: AH = -1640.1 kJ P4 (9) + 3 O2 (a) → P.O6 (e) Pa (0) +…

A: 1) P4 (s) + 3 O2(g) →→→ P406 (s) ∆H = - 1640.1kJ 2) P4 (s) + 5 O2(g) →→→ P4H10 (s) ∆H = - 2940.1kJ…

Q: A 1.75 mol sample of an ideal gas is allowed to expand adiabatically and reversibly to twice its…

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