Given: 0A OB Find 4 A chair is suspended from two different cables, AC and CB. B . the combined weight of the chair and person is 187 lb . theta A = 28 degrees . theta B = 39 degrees . the tension in cable CB= ##.## lbs
Given: 0A OB Find 4 A chair is suspended from two different cables, AC and CB. B . the combined weight of the chair and person is 187 lb . theta A = 28 degrees . theta B = 39 degrees . the tension in cable CB= ##.## lbs
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:### Suspension Mechanics: Resolving Forces in Two Cables
#### Example Problem: Chair Suspended by Cables
**Problem Description:**
A chair is suspended from two different cables, labeled AC and CB, converging at point C.
##### Given:
- The combined weight of the chair and person is 187 lb
- Angle \( \theta_A = 28 \) degrees
- Angle \( \theta_B = 39 \) degrees
**Objective:**
- Find the tension in cable CB.
###### Diagram Explanation:
The diagram depicts a man sitting on a chair, which is secured in place by two cables (AC and CB) meeting at point C. Cable AC forms an angle of \( \theta_A \) (28 degrees) with the vertical line through the midpoint of the chair, while cable CB forms an angle of \( \theta_B \) (39 degrees).
By analyzing this diagram, students can learn about resolving forces in equilibrium and using trigonometric relationships to determine tensions in the cables. The solution involves applying principles from static equilibrium and vector decomposition.
*To solve for the tension in cable CB, we need to use the sum of forces in both the x and y directions and apply trigonometric identities.*
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