Give the time complexity of the following method. void method1(int n) { } for (int i = n; i >= 1; i--) { } for (int j = n; j >= 1; j -= i) { System.out.println("*"); } Write Theta, O, or Omega for the symbol. Symbol: Write the function g(n), as in: n^2 n lg n n^(5/2) Function =
Give the time complexity of the following method. void method1(int n) { } for (int i = n; i >= 1; i--) { } for (int j = n; j >= 1; j -= i) { System.out.println("*"); } Write Theta, O, or Omega for the symbol. Symbol: Write the function g(n), as in: n^2 n lg n n^(5/2) Function =
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![**Title: Understanding Time Complexity in Algorithms**
**Give the time complexity of the following method:**
```java
void method1(int n) {
for (int i = n; i >= 1; i--) {
for (int j = n; j >= 1; j -= i) {
System.out.println("*");
}
}
}
```
**Determine the Time Complexity Symbol:**
- Write Theta, O, or Omega for the symbol.
- Symbol = [Input field for user]
**Determine the Function g(n):**
- Options for function g(n) include:
- \( n^2 \)
- \( n \log n \)
- \( n^{(5/2)} \)
- Function = [Input field for user]
**Explanation:**
The method `method1` involves nested loops. The outer loop runs `n` times, and for each iteration of the outer loop, the inner loop runs a decreasing number of times determined by the decrement `j -= i`. Understanding the time complexity involves analyzing how the total number of operations grows with respect to `n`.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F15fc1c7a-8086-4513-82cd-5088c3026e9c%2Ffaefb857-d6b4-4369-bb57-761f772fcfa8%2Fftvhozo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Understanding Time Complexity in Algorithms**
**Give the time complexity of the following method:**
```java
void method1(int n) {
for (int i = n; i >= 1; i--) {
for (int j = n; j >= 1; j -= i) {
System.out.println("*");
}
}
}
```
**Determine the Time Complexity Symbol:**
- Write Theta, O, or Omega for the symbol.
- Symbol = [Input field for user]
**Determine the Function g(n):**
- Options for function g(n) include:
- \( n^2 \)
- \( n \log n \)
- \( n^{(5/2)} \)
- Function = [Input field for user]
**Explanation:**
The method `method1` involves nested loops. The outer loop runs `n` times, and for each iteration of the outer loop, the inner loop runs a decreasing number of times determined by the decrement `j -= i`. Understanding the time complexity involves analyzing how the total number of operations grows with respect to `n`.
Expert Solution

Step 1
The code given:-
void method1 (int n) {
for (int i = n; i >= 1; i--) {
for (int j = n; j >= 1; j -= i) {
System.out.println("*");
}
}
}
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