Give the time complexity of the following method. void method1(int n) { } for (int i = n; i >= 1; i--) { } for (int j = n; j >= 1; j -= i) { System.out.println("*"); } Write Theta, O, or Omega for the symbol. Symbol: Write the function g(n), as in: n^2 n lg n n^(5/2) Function =

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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**Title: Understanding Time Complexity in Algorithms**

**Give the time complexity of the following method:**

```java
void method1(int n) {
    for (int i = n; i >= 1; i--) {
        for (int j = n; j >= 1; j -= i) {
            System.out.println("*");
        }
    }
}
```

**Determine the Time Complexity Symbol:**

- Write Theta, O, or Omega for the symbol.
- Symbol = [Input field for user]

**Determine the Function g(n):**

- Options for function g(n) include:
  - \( n^2 \)
  - \( n \log n \)
  - \( n^{(5/2)} \)

- Function = [Input field for user]

**Explanation:**

The method `method1` involves nested loops. The outer loop runs `n` times, and for each iteration of the outer loop, the inner loop runs a decreasing number of times determined by the decrement `j -= i`. Understanding the time complexity involves analyzing how the total number of operations grows with respect to `n`.
Transcribed Image Text:**Title: Understanding Time Complexity in Algorithms** **Give the time complexity of the following method:** ```java void method1(int n) { for (int i = n; i >= 1; i--) { for (int j = n; j >= 1; j -= i) { System.out.println("*"); } } } ``` **Determine the Time Complexity Symbol:** - Write Theta, O, or Omega for the symbol. - Symbol = [Input field for user] **Determine the Function g(n):** - Options for function g(n) include: - \( n^2 \) - \( n \log n \) - \( n^{(5/2)} \) - Function = [Input field for user] **Explanation:** The method `method1` involves nested loops. The outer loop runs `n` times, and for each iteration of the outer loop, the inner loop runs a decreasing number of times determined by the decrement `j -= i`. Understanding the time complexity involves analyzing how the total number of operations grows with respect to `n`.
Expert Solution
Step 1

The code given:-

void method1 (int n) {

for (int i = n; i >= 1; i--) {

for (int j = n; j >= 1; j -= i) {

System.out.println("*");

}

}

}

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