Give the product. O a.. O b.. Oc.. O d.. O e.. Of.. Br₂ (2 eq) (a) (b) A Moving to another question will save this response. Br Br Joe and (e) Br Br MacBook Air Br Br Br Br Br. Br Br

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### Bromination of an Alkyne on an Educational Website

#### Problem Statement:
**Give the product.**

An alkyne reacts with 2 equivalents of bromine (Br₂), and the goal is to determine which structure (a to f) is the resulting product.

#### Reaction Schema:

\[
 \text{Alkyne} \xrightarrow{\text{Br}_2 \, (\text{2 eq})} 
\]
The reactant and possible products are displayed as follows:

##### Reactant (Alkyne):
- A triple-bonded carbon structure (\[triple bond\]).

##### Reaction with Br₂ (2 equivalents):
- The alkyne undergoes a transformation when treated with 2 equivalents of bromine.

#### Potential Products:

- **(a)** A molecule with two bromine atoms each attached to a different carbon atom with single bonds.
  
  Structure:
  \[
    \begin{align*}
    & \quad Br \\
    -C-C \\
    & \quad Br
    \end{align*}
  \]
  
- **(b)** A molecule with two bromine atoms each attached to different carbon atoms of a previously triple-bonded structure, now with single bonds.

  Structure:
  \[
    \begin{align*}
    \quad \\
    Br-C-C-Br
    \end{align*}
  \]

- **(c)** A molecule with one carbon attached to three bromine atoms and a second carbon attached to one bromine atom, losing the triple bond structure.

  Structure:
  \[
    \begin{align*}
    \quad Br \\
    Br-C(+Br)-C \\
    & \quad Br
    \end{align*}
  \]

- **(d)** A molecule where two bromine atoms are attached to carbons in a different spatial orientation relative to other options.

  Structure:
  \[
    \begin{align*}
    \quad Br \\
    C=C-C(+Br)
    \end{align*}
  \]

- **(e)** A linear molecule with no bromine atoms, retaining a structure similar to the alkyne.

  Structure:
  \[
    \begin{align*}
    -C=C-C
    \end{align*}
  \]

- **(f)** A molecule with a staggered structure but no bromine
Transcribed Image Text:### Bromination of an Alkyne on an Educational Website #### Problem Statement: **Give the product.** An alkyne reacts with 2 equivalents of bromine (Br₂), and the goal is to determine which structure (a to f) is the resulting product. #### Reaction Schema: \[ \text{Alkyne} \xrightarrow{\text{Br}_2 \, (\text{2 eq})} \] The reactant and possible products are displayed as follows: ##### Reactant (Alkyne): - A triple-bonded carbon structure (\[triple bond\]). ##### Reaction with Br₂ (2 equivalents): - The alkyne undergoes a transformation when treated with 2 equivalents of bromine. #### Potential Products: - **(a)** A molecule with two bromine atoms each attached to a different carbon atom with single bonds. Structure: \[ \begin{align*} & \quad Br \\ -C-C \\ & \quad Br \end{align*} \] - **(b)** A molecule with two bromine atoms each attached to different carbon atoms of a previously triple-bonded structure, now with single bonds. Structure: \[ \begin{align*} \quad \\ Br-C-C-Br \end{align*} \] - **(c)** A molecule with one carbon attached to three bromine atoms and a second carbon attached to one bromine atom, losing the triple bond structure. Structure: \[ \begin{align*} \quad Br \\ Br-C(+Br)-C \\ & \quad Br \end{align*} \] - **(d)** A molecule where two bromine atoms are attached to carbons in a different spatial orientation relative to other options. Structure: \[ \begin{align*} \quad Br \\ C=C-C(+Br) \end{align*} \] - **(e)** A linear molecule with no bromine atoms, retaining a structure similar to the alkyne. Structure: \[ \begin{align*} -C=C-C \end{align*} \] - **(f)** A molecule with a staggered structure but no bromine
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