Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2. 2C8H18 + 24O2→16CO2 + 18H2O
Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2. 2C8H18 + 24O2→16CO2 + 18H2O
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2.
2C8H18 + 24O2→16CO2 + 18H2O
Expert Solution
Data given:
Number of moles of C8H18 = 4.000 moles
Number of moles of O2 = 4.000 moles
Balanced chemical reaction between C8H18 and O2 is given by :
2C8H18 + 24O2→16CO2 + 18H2O
As per the balanced chemical equation,
2 moles of C8H18 combines with 24 moles of O2.
Hence, 1 mole of C8H18 will combine with 12 moles of O2.
Therefore 4.000 moles of C8H18 will combine with
Hence, 4.000 moles of C8H18 will need 48.00 moles of O2..
But we have only 4.000 moles of O2 in our reaction mixture.
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