Give the exact number of multiplications performed in the following segment of an algorithm assuming a₁, ª2, ..., ª are positive real numbers and n = 11. for i=1 to n m₂ = a;; for j=i+1 to n mi = m;aj;

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Chapter2: Second-order Linear Odes
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**Algorithm Analysis: Counting Multiplications**

**Problem Statement:**
Determine the exact number of multiplications performed in the following segment of an algorithm. Assume \( a_1, a_2, \ldots, a_n \) are positive real numbers, with \( n = 11 \).

**Algorithm Segment:**

```
for i = 1 to n
    m_i = a_i;
    for j = i + 1 to n
        m_i = m_i a_j;
```

**Explanation:**

1. **Outer Loop:** The variable \( i \) iterates from 1 to \( n \).
2. **Initialization:** For each \( i \), the variable \( m_i \) is initialized as \( a_i \).
3. **Inner Loop:** The variable \( j \) iterates from \( i + 1 \) to \( n \).
   - In each iteration of the inner loop, \( m_i \) is updated as \( m_i \times a_j \).

**Total Multiplications:**

To find the total number of multiplications:
- For each iteration of \( i \), the inner loop runs \( (n - i) \) times (since \( j \) starts at \( i + 1 \)).
- Therefore, the number of multiplications for each \( i \) is \( n - i \).

Summing the multiplications over all iterations of the outer loop:

\[
\sum_{i=1}^{n} (n - i) = (n - 1) + (n - 2) + \ldots + 1 + 0
\]

This is the sum of the first \((n-1)\) natural numbers, which can be calculated using the formula:

\[
\frac{(n-1) \times n}{2}
\]

Substitute \( n = 11 \):

\[
\frac{10 \times 11}{2} = 55
\]

Thus, the exact number of multiplications performed is 55.
Transcribed Image Text:**Algorithm Analysis: Counting Multiplications** **Problem Statement:** Determine the exact number of multiplications performed in the following segment of an algorithm. Assume \( a_1, a_2, \ldots, a_n \) are positive real numbers, with \( n = 11 \). **Algorithm Segment:** ``` for i = 1 to n m_i = a_i; for j = i + 1 to n m_i = m_i a_j; ``` **Explanation:** 1. **Outer Loop:** The variable \( i \) iterates from 1 to \( n \). 2. **Initialization:** For each \( i \), the variable \( m_i \) is initialized as \( a_i \). 3. **Inner Loop:** The variable \( j \) iterates from \( i + 1 \) to \( n \). - In each iteration of the inner loop, \( m_i \) is updated as \( m_i \times a_j \). **Total Multiplications:** To find the total number of multiplications: - For each iteration of \( i \), the inner loop runs \( (n - i) \) times (since \( j \) starts at \( i + 1 \)). - Therefore, the number of multiplications for each \( i \) is \( n - i \). Summing the multiplications over all iterations of the outer loop: \[ \sum_{i=1}^{n} (n - i) = (n - 1) + (n - 2) + \ldots + 1 + 0 \] This is the sum of the first \((n-1)\) natural numbers, which can be calculated using the formula: \[ \frac{(n-1) \times n}{2} \] Substitute \( n = 11 \): \[ \frac{10 \times 11}{2} = 55 \] Thus, the exact number of multiplications performed is 55.
Expert Solution
Step 1

It is given that i=1 to 11 and then mi assign the value of ai and then j start from 2 to 11.

For the second loop it perform 10 times for i=1 and then stop and then again start from i=2.

For i=2, second for loop perform 9 times.

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