Give the exact number of multiplications performed in the following segment of an algorithm assuming a₁, ª2, ..., ª are positive real numbers and n = 11. for i=1 to n m₂ = a;; for j=i+1 to n mi = m;aj;
Give the exact number of multiplications performed in the following segment of an algorithm assuming a₁, ª2, ..., ª are positive real numbers and n = 11. for i=1 to n m₂ = a;; for j=i+1 to n mi = m;aj;
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![**Algorithm Analysis: Counting Multiplications**
**Problem Statement:**
Determine the exact number of multiplications performed in the following segment of an algorithm. Assume \( a_1, a_2, \ldots, a_n \) are positive real numbers, with \( n = 11 \).
**Algorithm Segment:**
```
for i = 1 to n
m_i = a_i;
for j = i + 1 to n
m_i = m_i a_j;
```
**Explanation:**
1. **Outer Loop:** The variable \( i \) iterates from 1 to \( n \).
2. **Initialization:** For each \( i \), the variable \( m_i \) is initialized as \( a_i \).
3. **Inner Loop:** The variable \( j \) iterates from \( i + 1 \) to \( n \).
- In each iteration of the inner loop, \( m_i \) is updated as \( m_i \times a_j \).
**Total Multiplications:**
To find the total number of multiplications:
- For each iteration of \( i \), the inner loop runs \( (n - i) \) times (since \( j \) starts at \( i + 1 \)).
- Therefore, the number of multiplications for each \( i \) is \( n - i \).
Summing the multiplications over all iterations of the outer loop:
\[
\sum_{i=1}^{n} (n - i) = (n - 1) + (n - 2) + \ldots + 1 + 0
\]
This is the sum of the first \((n-1)\) natural numbers, which can be calculated using the formula:
\[
\frac{(n-1) \times n}{2}
\]
Substitute \( n = 11 \):
\[
\frac{10 \times 11}{2} = 55
\]
Thus, the exact number of multiplications performed is 55.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faad9e4ed-ed50-4fe3-96ca-72ed3d364f6f%2Fb284b58a-7e72-4eda-80fb-1a5fcb8187b8%2Flyx6dll_processed.png&w=3840&q=75)
Transcribed Image Text:**Algorithm Analysis: Counting Multiplications**
**Problem Statement:**
Determine the exact number of multiplications performed in the following segment of an algorithm. Assume \( a_1, a_2, \ldots, a_n \) are positive real numbers, with \( n = 11 \).
**Algorithm Segment:**
```
for i = 1 to n
m_i = a_i;
for j = i + 1 to n
m_i = m_i a_j;
```
**Explanation:**
1. **Outer Loop:** The variable \( i \) iterates from 1 to \( n \).
2. **Initialization:** For each \( i \), the variable \( m_i \) is initialized as \( a_i \).
3. **Inner Loop:** The variable \( j \) iterates from \( i + 1 \) to \( n \).
- In each iteration of the inner loop, \( m_i \) is updated as \( m_i \times a_j \).
**Total Multiplications:**
To find the total number of multiplications:
- For each iteration of \( i \), the inner loop runs \( (n - i) \) times (since \( j \) starts at \( i + 1 \)).
- Therefore, the number of multiplications for each \( i \) is \( n - i \).
Summing the multiplications over all iterations of the outer loop:
\[
\sum_{i=1}^{n} (n - i) = (n - 1) + (n - 2) + \ldots + 1 + 0
\]
This is the sum of the first \((n-1)\) natural numbers, which can be calculated using the formula:
\[
\frac{(n-1) \times n}{2}
\]
Substitute \( n = 11 \):
\[
\frac{10 \times 11}{2} = 55
\]
Thus, the exact number of multiplications performed is 55.
Expert Solution
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Step 1
It is given that to and then assign the value of and then start from to .
For the second loop it perform times for and then stop and then again start from .
For , second for loop perform times.
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