Give the domain and range of the function. W 2 12345 OA. Domain: (-5,5) Range: [-2,8) OB. Domain: (-00,00) Range: [-2,4] OC. Domain: (-00,00) Range: [0,00) O D. Domain: (-00,00) Range: [-2,00)

Q: y=-2/3x+3 y = 3/2x+1 y=-2/3x + 1 y = -3/2x+3

A:

Q: Evaluate if x=4,8,3,-2 ∑x ∑x+1 ∑(x+1) 3∑x - 4

A: Given that  if x=4,8,3,-2

Q: Find the distance between -5 and 3 on the real number line.

A: The distance between -5 and 3 on the real number line is,

Q: A(1,-3),B(1,1),C(5,1),D(5,-3) translation of 3 units left and 5 units up.

A:

Q: Simplify : [(2 - 6/(x + 1).( 1 + 3 / (x - 2)]

A:

Q: Find (1, -5) (7, 9).

A:

Q: The graph of y = x° is transformed as shown in the graph below. Which equation represents the…

A: Given,graph of y=x2 is transformed as shown in the graph belowwe have to find the equation…

Q: COMPLETE Evaluate x) for x=-3. " (-3) = %3D DONE

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Q: 27. (xa is an odd number between and 9, inclusive}

A:

Q: Plot the inverse (-6,7) (0,4)

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Q: Evaluate the expression if x = - 2 and y = 3. 2x/ (x - y)

A: 2x/(x-y)

Q: (1. 2) (3.-2) (-1.-2) (4.-3)

A: Integral of a function from a to b= area of the function from x=a to x=b

Q: -1 = tanO/2

A: over

Q: To-42 5-2X-3 (6z) odz dy oe aly de

A:

Q: -9条-x+x

A: The given differential equation is: -ydydx-xy2+x=0

Q: Domain: yig sh Domain: Range: Range: 3.

A:

Q: y = x 2 - 4x + 3 y =x - 1

A: Given area is bounded by the curves, y=x2-4x+3   and y=x-1

Q: 11 = x + (-17) X= ?

A:

Q: Solve: 2 (4³) + 9 = 169

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Q: Find (-8, 6)· (5, 1).

A:

Q: 3.) Simplify (0.75x + 2y) - (0.3x – 0.6y)

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Q: /- wiite ay 2. -5

A:

Q: Express −4 iª -4 i in the form [a, b]:

A: The vector is given by -4i→ To evaluate: The vector in the form a, b.

Q: Au = and Aü = -1 then A(-3u- 30)

A: solution is given below

Q: Choose the domain of the relation: (-1, 1, 3,4) All real numbers {-4, -1. 1, 3, 4) {-4, 1, 3)

A: d is correct Domain {-4,1,3}

Q: find the inverse

A: TO FIND  THE INVERSE OF THE MATRIX LET A= 1-222-313-41 FORMULA USED A-1= (AdjA)'A A not equal to…

Q: To-22 (1ny-8x) dy da

A:

Q: Let = 2 4-8 L and = 0 Then proj= CO -4 3

A:

Q: Translate the interval (79,106) into plus/minus notation.

A: Given information- We have given the interval = (79, 106) We know that- Confidence interval = Mean ±…

Q: {(-5, 7), (-6, -8), (1, -2), (10, 3) }

A:

Q: -2/w-3/4=3w-7/3

A: Consider the given equation.