Give the condensed formulas (or names) of the products formed from the following reaction. [H] S.

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**Educational Content: Reaction Analysis**

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**Question:**

Give the condensed formulas (or names) of the products formed from the following reaction.

**Reaction:**

The reactant is a linear compound depicted as follows:
- A chain of five atoms is shown: C—C—S—S—C—C, where each C represents a carbon atom and each S represents a sulfur atom.
- The compound appears to be a disulfide linked to alkane chains.
  
- The reaction involves a reducing agent denoted as "[H]".

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**Explanation:**

This diagram illustrates a chemical reaction involving the reduction of a disulfide bond (S—S). The disulfide is positioned between two alkyl groups, represented as —CH2—CH2—. When exposed to a reducing agent, the disulfide bond typically cleaves, leading to the formation of two thiol groups (—SH).

**Expected Products:**

Upon reduction, the disulfide link will break, producing:

1. Two molecules of 1-ethanethiol (ethanethiol).
   
**Condensed Formula:**

The product can be represented as C2H5SH for each thiol molecule, given the ethyl (—C2H5) group attached to the sulfur (S).

This reaction is a common method to break disulfide bonds in organic chemistry and is fundamental in understanding thiol-disulfide exchange reactions.
Transcribed Image Text:**Educational Content: Reaction Analysis** --- **Question:** Give the condensed formulas (or names) of the products formed from the following reaction. **Reaction:** The reactant is a linear compound depicted as follows: - A chain of five atoms is shown: C—C—S—S—C—C, where each C represents a carbon atom and each S represents a sulfur atom. - The compound appears to be a disulfide linked to alkane chains. - The reaction involves a reducing agent denoted as "[H]". --- **Explanation:** This diagram illustrates a chemical reaction involving the reduction of a disulfide bond (S—S). The disulfide is positioned between two alkyl groups, represented as —CH2—CH2—. When exposed to a reducing agent, the disulfide bond typically cleaves, leading to the formation of two thiol groups (—SH). **Expected Products:** Upon reduction, the disulfide link will break, producing: 1. Two molecules of 1-ethanethiol (ethanethiol). **Condensed Formula:** The product can be represented as C2H5SH for each thiol molecule, given the ethyl (—C2H5) group attached to the sulfur (S). This reaction is a common method to break disulfide bonds in organic chemistry and is fundamental in understanding thiol-disulfide exchange reactions.
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