**Transcription for Educational Website**---**Topic: Reaction Mechanisms****I. Give complete mechanism of following reactions:****a.**1. \( \text{CH}_3 \, \overset{\text{H}}{\underset{\text{O}}{-}} \, \text{C} \, \text{CH} \, \text{CH}_3 \xrightarrow{\text{HBr}} \text{(CH}_3\text{)}_3 \, \text{C} \, \overset{\text{Br}}{\underset{\text{CH}_3}{\equiv}} \) \( \text{H}_2\text{O} \) - Intermediate: \(\text{A}\) - By-products: \(\text{(CH}_3\text{)}_3 \text{C} \equiv \text{CH}_2 + (\text{CH}_3)_2 \text{C} = \text{CH(CH}_3)_2\) - By-products: \(\text{D}\), \(\text{E}\)**b.**- Reactants: A hydrocarbon chain undergoes a reaction with \(\text{H}_3\text{O}^+\), leading to a cyclic product.**c.**- Reactants: A substituted benzene ring reacts with a hydrocarbon chain, forming a new carbon-carbon bond with retention of the substituents.---### Detailed Diagram Explanation:**Reaction a:**- **Mechanism:** - The primary alcohol reacts with HBr, resulting in the formation of a tertiary alkyl bromide. - Water is expelled during the reaction. - The process progresses through intermediates denoted by symbols \(\text{A}\), \(\text{D}\), and \(\text{E}\).**Reaction b:**- **Diagram Description:** - The linear hydrocarbon chain reacts in an acidic aqueous medium. The reaction yields a cyclized product, suggesting intramolecular bonding facilitated by hydronium ion (\(\text{H}_3\text{O}^+\)) catalysis.**Reaction c:**- **Diagram Description:** - The image shows the interaction between a substituted benzene ring featuring a bulky group and an aliphatic hydrocarbon chain. The formation of a new covalent ### Reaction Scheme for Aldol Reaction#### Part d:This part of the reaction involves the formation of a carbonyl compound via an Aldol reaction. The process is described as follows:1. **Starting Materials:** - A compound with a carbonyl group (\( \text{C=O} \)) and an attached hydrogen (\( \text{C-H} \)). - Reacts with sodium hydride (\( \text{NaCH} \)) and a benzyl compound (\( \text{C} \) - \( \text{BR} \)).2. **Reaction Process:** - In the first step, sodium hydride (\( \text{NaCH} \)) is used.3. **Reaction Outcome:** - The product is a benzyl-ketone with a carbonyl group attached to the benzene ring: \( \text{C} \) - \( \text{O} \)-\( \text{C=O} \).#### Part e:This part focuses on the stereochemistry and the formation of a racemic mixture.1. **Starting Materials:** - An \( \text{R-isomer} \) of a benzyl compound with a leaving group (\( \text{BR} \)). - Acetone (\( \text{CH}_3-\overset{\uparrow}{C}=O-\overset{\uparrow}{H} \)).2. **Reaction Outcome:** - The isomer reacts to form a racemic mixture of the product, which is a benzene derivative with a ketone (\( \text{O} = \overset{\uparrow}{C}-\overset{\uparrow}{CH}_3 \)) group. - Byproduct is \( \text{HBY} \).### Explanation:The reaction outlines the transformation of reactants using basic organic reaction techniques such as the Aldol reaction. The stereochemical notation indicates consideration of chiral centers, resulting in racemic mixtures.

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Give complete mechanism of following reactions: CH, 0-H HBr CH; --C-CH–CH, → (CH,), C–CE–CH; a. H;O b. CH, Br + (CH;)C- CH = CH; + (CH) ;С— сH (сH); + (CH3); C = C (CH,); CH2 =C-CH (CH;)? CH3