Give both solutions to the equation 4 cos(x) – 3 = cos(x) – 5 - where 0° < x < 360°. Round your answers to the nearest degree. Blank # 1 Blank # 2

Q: Solve 2 cos x -1=0 for æ, where 0 < x < 360°. %3D O 60°, 300° O 30° only O 30°, 150°

A: Given :- 2cosx-1=0 for x, where 0≤x≤360° We have to find:- The value of x.

Q: cos 2.

A: Using the trigonometric formula,  cos2θ=2cos2θ-1⇒cos2θ+1=2cos2θ⇒cos2θ+12=cos2θ⇒cos2θ=cos2θ+12 Taking…

Q: Which of the following equations best models this situation? A bicycle tire with a radius of 40 cm…

A: The radius of the bicycle tire = 40 cm and tire rotate once every 2 seconds.

Q: a Sketch the graph of y = sine for 0° s 0 s 360°. %3D b Use your graph to solve the equation sin =…

A: The graph of y=sinθ for 0°≤θ≤360° is as follows

Q: for 4Cos2x=3.7 s2x +

A: Please refer to the image below

Q: 2. Solve for x in the equation: sin 2x = 2 cos x. C. 90° D. 100° A. 80° B. 95°

A:

Q: sin 0 = sin 2e %3D T 3n 5T 1ln A) 3 4 3 6 5T It, 3 B) 0. 3 7n 11T C) {0, T} D) 0, 6 6 6. 6.

A: We will simply  the equation first and then find values of theta that satisfy the equation

Q: CoS 2n du.

A:

Q: Cos(47°)=x/8

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.