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Give both an exact solution and an approximate solution to two decimal places for the following. Given: right AABC with m¿C = 90° and m¿BAC = 60° point D on BC AD bisects BAC and AC = 3/3 Find: BD A B exact BD = approximate BD =

Give both an exact solution and an approximate solution to two decimal places for the following. Given: right AABC with m¿C = 90° and m¿BAC = 60° point D on BC AD bisects BAC and AC = 3/3 Find: BD A B exact BD = approximate BD =

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement:** Give both an exact solution and an approximate solution to two decimal places for the following. **Given:** - Right triangle \( \triangle ABC \) with \( m\angle C = 90^\circ \) and \( m\angle BAC = 60^\circ \) - Point \( D \) on \( BC \) - \( AD \) bisects \( \angle BAC \) and \( AC = 3\sqrt{3} \) **Find:** - \( BD \) **Diagram Explanation:** The diagram shows a right triangle \( \triangle ABC \) with: - \( B \) at the bottom-left vertex, - \( C \) at the bottom-right vertex, - \( A \) at the top vertex. - A line \( AD \) bisects \( \angle BAC \). - \( D \) is a point on \( BC \). **Solutions:** - Exact value: \( BD = \) - Approximate value: \( BD = \)
Transcribed Image Text:**Problem Statement:** Give both an exact solution and an approximate solution to two decimal places for the following. **Given:** - Right triangle \( \triangle ABC \) with \( m\angle C = 90^\circ \) and \( m\angle BAC = 60^\circ \) - Point \( D \) on \( BC \) - \( AD \) bisects \( \angle BAC \) and \( AC = 3\sqrt{3} \) **Find:** - \( BD \) **Diagram Explanation:** The diagram shows a right triangle \( \triangle ABC \) with: - \( B \) at the bottom-left vertex, - \( C \) at the bottom-right vertex, - \( A \) at the top vertex. - A line \( AD \) bisects \( \angle BAC \). - \( D \) is a point on \( BC \). **Solutions:** - Exact value: \( BD = \) - Approximate value: \( BD = \)
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