Give an example of an integral that is both type 1 and type 2. Then rewrite the integral using the appropriate limits.

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Improper integrals! Give an example of an improper integral that is type one and type two. Then rewrite the integral with proper limits. Thank you! PLease show all work!

**Problem Statement:**
  
Give an example of an integral that is both type 1 and type 2. Then rewrite the integral using the appropriate limits.

---

**Understanding Types of Improper Integrals:**

- **Type 1 Improper Integrals**: These occur when one or both limits of integration are infinite.
  
- **Type 2 Improper Integrals**: These arise when the integrand has an infinite discontinuity in the interval of integration.

**Example:**

Consider the integral:

\[ \int_{1}^{\infty} \frac{1}{(x-1)^{3/2}} \, dx \]

- **Analysis**:
  - **Type 1**: The upper limit is infinity, making it a type 1 improper integral.
  - **Type 2**: The integrand \( \frac{1}{(x-1)^{3/2}} \) becomes undefined as \( x \to 1^+ \), showing a discontinuity at \( x=1 \).

- **Rewriting with Limits**:
  To evaluate, rewrite using limits:

  \[ \lim_{b \to \infty} \lim_{a \to 1^+} \int_{a}^{b} \frac{1}{(x-1)^{3/2}} \, dx \]

This expression accounts for both the infinite limit and the discontinuity, allowing the integral to be properly evaluated if it converges.
Transcribed Image Text:**Problem Statement:** Give an example of an integral that is both type 1 and type 2. Then rewrite the integral using the appropriate limits. --- **Understanding Types of Improper Integrals:** - **Type 1 Improper Integrals**: These occur when one or both limits of integration are infinite. - **Type 2 Improper Integrals**: These arise when the integrand has an infinite discontinuity in the interval of integration. **Example:** Consider the integral: \[ \int_{1}^{\infty} \frac{1}{(x-1)^{3/2}} \, dx \] - **Analysis**: - **Type 1**: The upper limit is infinity, making it a type 1 improper integral. - **Type 2**: The integrand \( \frac{1}{(x-1)^{3/2}} \) becomes undefined as \( x \to 1^+ \), showing a discontinuity at \( x=1 \). - **Rewriting with Limits**: To evaluate, rewrite using limits: \[ \lim_{b \to \infty} \lim_{a \to 1^+} \int_{a}^{b} \frac{1}{(x-1)^{3/2}} \, dx \] This expression accounts for both the infinite limit and the discontinuity, allowing the integral to be properly evaluated if it converges.
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