Give a proof by contraposition of the following statement. If x is an integer and square of x is even, then x is even.
Give a proof by contraposition of the following statement. If x is an integer and square of x is even, then x is even.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
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
Transcribed Image Text:**Mathematical Propositions and Proofs**
**Topic: Proof by Contraposition**
**The Statement:**
"Give a proof by contraposition of the following statement."
- **If \( x \) is an integer and the square of \( x \) is even, then \( x \) is even.**
**Concept Overview:**
In mathematics, a proof by contraposition is a powerful technique used to prove statements of the form "If \( P \), then \( Q \)." Instead of proving this directly, we can equivalently prove the contrapositive statement: "If not \( Q \), then not \( P \)."
**Application to the Given Statement:**
**Original Statement:**
If \( x \) is an integer and the square of \( x \) is even, then \( x \) is even.
**Contrapositive Statement:**
If \( x \) is not even (i.e., \( x \) is odd), then the square of \( x \) is not even (i.e., the square of \( x \) is odd).
**Proof by Contraposition:**
1. **Start with the assumption that \( x \) is odd.**
- An integer \( x \) is odd if it can be written in the form: \( x = 2k + 1 \), where \( k \) is an integer.
2. **Square both sides to find the square of \( x \):**
- \( x^2 = (2k + 1)^2 \)
- \( x^2 = 4k^2 + 4k + 1 \)
- \( x^2 = 2(2k^2 + 2k) + 1 \)
3. **Analyze the resulting expression:**
- The expression \( 2(2k^2 + 2k) \) is clearly even since it is multiplied by 2.
- Adding 1 to an even number yields an odd number.
4. **Conclude that the square of \( x \) is odd:**
- Therefore, \( x^2 \) is odd when \( x \) is odd.
By proving the contrapositive statement, we have effectively proven the original statement: If \( x \) is an integer and the square of \( x \) is even, then \( x \) is even.
This concludes the
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