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Give a formula F = M(x,y)i + N(x,y)j for the vector field in the plane that has the property that F points toward the origin with magnitude inversely proportional to the square of the distance from (x,y) to the origin. (The field is not defined at the origin. Choose the correct answer below. OA. F=- А. OB. F= OC, F= ос. OD. kx 2 x+y F=- kx 2 x² + y² i- kx ky 3/2i+ 3/2j, (x² + y²) ³/2 ² + (x² +1²) ²1/2¹1. k> (x²+x²) O ky x² + y² şi+ kx (²²) ³ ky j.k>0 j.k>0 ky (1²2) 3/21. K>0 3/2 1-

Give a formula F = M(x,y)i + N(x,y)j for the vector field in the plane that has the property that F points toward the origin with magnitude inversely proportional to the square of the distance from (x,y) to the origin. (The field is not defined at the origin. Choose the correct answer below. OA. F=- А. OB. F= OC, F= ос. OD. kx 2 x+y F=- kx 2 x² + y² i- kx ky 3/2i+ 3/2j, (x² + y²) ³/2 ² + (x² +1²) ²1/2¹1. k> (x²+x²) O ky x² + y² şi+ kx (²²) ³ ky j.k>0 j.k>0 ky (1²2) 3/21. K>0 3/2 1-

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 31E
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Give a formula F = M(x,y)i + N(x,y)j for the vector field in the plane that has the property that F points toward the origin with magnitude inversely proportional to the square of the distance from (x,y) to the origin. (The field is not defined at the origin.) Choose the correct answer below. kx ky O A. F=-22-221.k>0 +y x +y OB. kx ky (x² + y²) ³/² (x² + y²) ³1² 3/2 i (x²+x²) O D. F= c. OC, F=. F= ky kx -i+ 2 2 2 x+y x +y -j.k> 0 k 3/2j, k>0 312 1.1 kx ky (x²+x²) ³3121- ਨਾਨਾ (x² + y²) 3/2 √, k> 0
Transcribed Image Text:Give a formula F = M(x,y)i + N(x,y)j for the vector field in the plane that has the property that F points toward the origin with magnitude inversely proportional to the square of the distance from (x,y) to the origin. (The field is not defined at the origin.) Choose the correct answer below. kx ky O A. F=-22-221.k>0 +y x +y OB. kx ky (x² + y²) ³/² (x² + y²) ³1² 3/2 i (x²+x²) O D. F= c. OC, F=. F= ky kx -i+ 2 2 2 x+y x +y -j.k> 0 k 3/2j, k>0 312 1.1 kx ky (x²+x²) ³3121- ਨਾਨਾ (x² + y²) 3/2 √, k> 0
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