gionStuuents died an average of o nou up a ny nean number of hours studied at your school is different from the reported 116 hour benchmark. Complete parts (a) through (c) belaw. State the null and alternative hypotheses. Choose the coffect answer below DA He =11.6 O B. Ho. a= 11.6 C Ho az116 O D. Ho: X÷11 6 Hi ß±116 Hq=116 H X=116 DE He az116 Hi 8= 116 OF Ho H#116 Hi p=11.6 OG Họ µ=116 出X=116 OH Ho Hz116 H X=116 OK H, B±116 OJ. Ho: B=116 Hi ß±116 OL H, X=116 Hi X# 11.6 OL He a= 116 H, B= 11 6 910日

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**Educational Website Content**

In a study conducted by a magazine, it was reported that at the top 50 business schools in a region, students averaged 11.6 hours of study. The objective is to test the hypothesis that the mean number of study hours at your school is different from this reported benchmark of 11.6 hours. To accomplish this, we need to determine the appropriate null and alternative hypotheses.

**a. State the null and alternative hypotheses. Choose the correct answer below:**

Options:
- **A.**
  - \( H_0: \mu = 11.6 \)
  - \( H_1: \mu \neq 11.6 \)

- **B.**
  - \( H_0: \alpha = 11.6 \)
  - \( H_1: \beta \neq 11.6 \)

- **C.**
  - \( H_0: \alpha \neq 11.6 \)
  - \( H_1: \alpha = 11.6 \)

- **D.**
  - \( H_0: \bar{X} = 11.6 \)
  - \( H_1: \bar{X} = 11.6 \)

- **E.**
  - \( H_0: \alpha = 11.6 \)
  - \( H_1: \beta = 11.6 \)

- **F.**
  - \( H_0: \mu \neq 11.6 \)
  - \( H_1: \mu = 11.6 \)

- **G.**
  - \( H_0: \mu = 11.6 \)
  - \( H_1: \bar{X} = 11.6 \)

- **H.**
  - \( H_0: \mu \neq 11.6 \)
  - \( H_1: \bar{X} = 11.6 \)

- **I.**
  - \( H_0: \alpha = 11.6 \)
  - \( H_1: \alpha \neq 11.6 \)

- **J.**
  - \( H_0: \beta = 11.6 \)
  - \( H_1: \beta \neq 11.6 \)

- **K.**
  - \( H
Transcribed Image Text:**Educational Website Content** In a study conducted by a magazine, it was reported that at the top 50 business schools in a region, students averaged 11.6 hours of study. The objective is to test the hypothesis that the mean number of study hours at your school is different from this reported benchmark of 11.6 hours. To accomplish this, we need to determine the appropriate null and alternative hypotheses. **a. State the null and alternative hypotheses. Choose the correct answer below:** Options: - **A.** - \( H_0: \mu = 11.6 \) - \( H_1: \mu \neq 11.6 \) - **B.** - \( H_0: \alpha = 11.6 \) - \( H_1: \beta \neq 11.6 \) - **C.** - \( H_0: \alpha \neq 11.6 \) - \( H_1: \alpha = 11.6 \) - **D.** - \( H_0: \bar{X} = 11.6 \) - \( H_1: \bar{X} = 11.6 \) - **E.** - \( H_0: \alpha = 11.6 \) - \( H_1: \beta = 11.6 \) - **F.** - \( H_0: \mu \neq 11.6 \) - \( H_1: \mu = 11.6 \) - **G.** - \( H_0: \mu = 11.6 \) - \( H_1: \bar{X} = 11.6 \) - **H.** - \( H_0: \mu \neq 11.6 \) - \( H_1: \bar{X} = 11.6 \) - **I.** - \( H_0: \alpha = 11.6 \) - \( H_1: \alpha \neq 11.6 \) - **J.** - \( H_0: \beta = 11.6 \) - \( H_1: \beta \neq 11.6 \) - **K.** - \( H
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Step 1

The hypothesis is a statement which states the claim related to the population parameter. 

Here, the test is conducted regarding the population mean which is denoted by 

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