gionStuuents died an average of o nou up a ny nean number of hours studied at your school is different from the reported 116 hour benchmark. Complete parts (a) through (c) belaw. State the null and alternative hypotheses. Choose the coffect answer below DA He =11.6 O B. Ho. a= 11.6 C Ho az116 O D. Ho: X÷11 6 Hi ß±116 Hq=116 H X=116 DE He az116 Hi 8= 116 OF Ho H#116 Hi p=11.6 OG Họ µ=116 出X=116 OH Ho Hz116 H X=116 OK H, B±116 OJ. Ho: B=116 Hi ß±116 OL H, X=116 Hi X# 11.6 OL He a= 116 H, B= 11 6 910日

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Amagazine reported that at the top 50 business schools in a region, students studied an average of 11.6 hours. Set up a hypothesis test to try to prove that the
mean number of hours studied at your school is different from the reported 11.6 hour benchmark. Complete parts (a) through (c) below.
a State the null and alternative hypotheses. Choose the cofrect answer below
OA Họ p=116
Hp116
O B. Ho a= 11.6
Hị ß#116
O D. Họ X÷11 6
Hi X=11.6
推CHaz116
Ha=116
OF H u#116
OE H az116
Hi B=116
OG Ho H=116
OH Ho p#116
Hi µ= 11.6
出 X2116
Hi X= 11.6
OK H B-116
Hi B= 11 6
OL Ho: X=11.6
H X+11 6
OL Ho a=116
OJ. Ho B=116
H B#116
Haz116
Transcribed Image Text:Amagazine reported that at the top 50 business schools in a region, students studied an average of 11.6 hours. Set up a hypothesis test to try to prove that the mean number of hours studied at your school is different from the reported 11.6 hour benchmark. Complete parts (a) through (c) below. a State the null and alternative hypotheses. Choose the cofrect answer below OA Họ p=116 Hp116 O B. Ho a= 11.6 Hị ß#116 O D. Họ X÷11 6 Hi X=11.6 推CHaz116 Ha=116 OF H u#116 OE H az116 Hi B=116 OG Ho H=116 OH Ho p#116 Hi µ= 11.6 出 X2116 Hi X= 11.6 OK H B-116 Hi B= 11 6 OL Ho: X=11.6 H X+11 6 OL Ho a=116 OJ. Ho B=116 H B#116 Haz116
Expert Solution
Step 1

The hypothesis is a statement which states the claim related to the population parameter. 

Here, the test is conducted regarding the population mean which is denoted by 

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