**Problem Statement:**A high jumper leaves the ground with an initial velocity of 11.1 m/s rightward at an angle of 17°. What is the high jumper’s initial horizontal velocity, in m/s?**Answer:** _______ m/s**Explanation:**To find the initial horizontal velocity, use the formula for the horizontal component of velocity:\[ v_{\text{horizontal}} = v \cdot \cos(\theta) \]Where:- \( v \) is the initial velocity (11.1 m/s),- \( \theta \) is the angle with respect to the horizontal (17°),- \( \cos \) is the cosine function. By calculating the cosine of 17° and multiplying it by 11.1 m/s, you can find the initial horizontal velocity.

Name: **Problem Statement:**A high jumper leaves the ground with an initial
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Description: **Problem Statement:**A high jumper leaves the ground with an initial velocity of 11.1 m/s rightward at an angle of 17°. What is the high jumper’s initial horizontal velocity, in m/s?**Answer:** _______ m/s**Explanation:**To find the initial horizon

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ghtward at an angle of 17°. What is the high jumper's initial h elocity, in m/s? nswer: m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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**Problem Statement:**

A high jumper leaves the ground with an initial velocity of 11.1 m/s rightward at an angle of 17°. What is the high jumper’s initial horizontal velocity, in m/s?

**Answer:** _______ m/s

**Explanation:**

To find the initial horizontal velocity, use the formula for the horizontal component of velocity:

\[ v_{\text{horizontal}} = v \cdot \cos(\theta) \]

Where:
- \( v \) is the initial velocity (11.1 m/s),
- \( \theta \) is the angle with respect to the horizontal (17°),
- \( \cos \) is the cosine function.

By calculating the cosine of 17° and multiplying it by 11.1 m/s, you can find the initial horizontal velocity.

Expert Solution

Step 1

Given

Initial velocity , u = 11.1 m/s

Angle, θ = 17^o

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