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gets a bonus of 50% of their monthly salary. What is the new mean and standard deviation after the bonus has been added? A. Mean = 16 000, Standard deviation = 3 450 B. Mean = 16 000, Standard deviation = 2 300 O C. Mean = 24 000, Standard deviation = 2 300 O D. Mean = 24 000, Standard deviation = 3 450

gets a bonus of 50% of their monthly salary. What is the new mean and standard deviation after the bonus has been added? A. Mean = 16 000, Standard deviation = 3 450 B. Mean = 16 000, Standard deviation = 2 300 O C. Mean = 24 000, Standard deviation = 2 300 O D. Mean = 24 000, Standard deviation = 3 450

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The mean monthly net salary of all employees at a medium sized company based in Durban is R16 000 and the standard deviation is R2300. During the month of December 2022, the company decides to award a bonus to its employees. In addition to their salary, each employee gets a bonus of 50% of their monthly salary. What is the new mean and standard deviation after the bonus has been added? A. Mean = 16 000, Standard deviation = 3 450 B. Mean = 16 000, Standard deviation = 2 300 O C. Mean = 24 000, Standard deviation = 2 300 O D. Mean = 24 000, Standard deviation = 3 450
Transcribed Image Text:The mean monthly net salary of all employees at a medium sized company based in Durban is R16 000 and the standard deviation is R2300. During the month of December 2022, the company decides to award a bonus to its employees. In addition to their salary, each employee gets a bonus of 50% of their monthly salary. What is the new mean and standard deviation after the bonus has been added? A. Mean = 16 000, Standard deviation = 3 450 B. Mean = 16 000, Standard deviation = 2 300 O C. Mean = 24 000, Standard deviation = 2 300 O D. Mean = 24 000, Standard deviation = 3 450
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Step 1: Given information:

It is given that 

Mean = 16000

Standard deviation = 2300

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