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Get the total response of the LTI system step input and initial conditions y(0) + 3 dy(t) d²y(t) dt² + 2y(t) = 4x(t) dt 0 = described by the differential equation below for a unit dy(0) = 0. dt O a. y(t) = ○ b. y(t) = (2e¯¹ – e- (2e-te-2t+2)u(t) -2t O c. y(t) = (6e-t – 3e- +2)u(t) ○ d. y(t) = (–2e¯t +e-²t +2)u(t)

Get the total response of the LTI system step input and initial conditions y(0) + 3 dy(t) d²y(t) dt² + 2y(t) = 4x(t) dt 0 = described by the differential equation below for a unit dy(0) = 0. dt O a. y(t) = ○ b. y(t) = (2e¯¹ – e- (2e-te-2t+2)u(t) -2t O c. y(t) = (6e-t – 3e- +2)u(t) ○ d. y(t) = (–2e¯t +e-²t +2)u(t)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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signals and systems

Get the total response of the LTI system step input and initial conditions y(0) + 3 dy(t) d²y(t) dt² + 2y(t) = 4x(t) dt 0 = described by the differential equation below for a unit dy(0) = 0. dt O a. y(t) = ○ b. y(t) = (2e¯¹ – e- (2e-te-2t+2)u(t) -2t O c. y(t) = (6e-t – 3e- +2)u(t) ○ d. y(t) = (–2e¯t +e-²t +2)u(t)
Transcribed Image Text:Get the total response of the LTI system step input and initial conditions y(0) + 3 dy(t) d²y(t) dt² + 2y(t) = 4x(t) dt 0 = described by the differential equation below for a unit dy(0) = 0. dt O a. y(t) = ○ b. y(t) = (2e¯¹ – e- (2e-te-2t+2)u(t) -2t O c. y(t) = (6e-t – 3e- +2)u(t) ○ d. y(t) = (–2e¯t +e-²t +2)u(t)
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