Subject Thermodynamics. Instructions: Don't round off in the process. Just round off in the final answer with 2 decimals only. Use 273.15 K to convert Celsius to Kelvin An ideal vapor-compressionrefrigeration cycle that usesrefrigerant-134a as itsworking fluid maintains acondenser at 800kPa andthe evaporator at -12°C.Determine the amount ofpower (kW) required toservice a 5792.6kW coolingload.T23 /0.8 МPа-12°C4s 4QiT =-12°C h =hg @ -1rc = 243.34 kJ/kgS1 = Sg @ -12°c =0.93925 kJ/kg - Ksat. vaporP = 0.8 MPas2 = S1h2 = 273.71kJ/kgP3 = 0.8 MPasat. liquidh3 = h5 @1MP2 =95.48 kJ/kgh4 = h3 = 95.48 kJ/kg (throttling)

Answered: geration cycle gerant-134a as

Engineering

Mechanical Engineering

geration cycle gerant-134a as

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Subject Thermodynamics. Instructions: Don't round off in the process. Just round off in the final answer with 2 decimals only. Use 273.15 K to convert Celsius to Kelvin

An ideal vapor-compression
refrigeration cycle that uses
refrigerant-134a as its
working fluid maintains a
condenser at 800kPa and
the evaporator at -12°C.
Determine the amount of
power (kW) required to
service a 5792.6kW cooling
load.
T
2
3 /0.8 МPа
-12°C
4s 4
Qi
T =-12°C h =hg @ -1rc = 243.34 kJ/kg
S1 = Sg @ -12°c =0.93925 kJ/kg - K
sat. vapor
P = 0.8 MPa
s2 = S1
h2 = 273.71kJ/kg
P3 = 0.8 MPa
sat. liquid
h3 = h5 @1MP2 =95.48 kJ/kg
h4 = h3 = 95.48 kJ/kg (throttling)

Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.

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