Identify the means and extremes of the following proportion. Then solve for m. 12 18 m 28 = 12 18 The extremes in the proportion == m 28 (Use a comma to separate answers as needed.) m= 12 18 The means in the proportion m 28 (Use a comma to separate answers as needed.) (Simplify your answer.) are = are
Identify the means and extremes of the following proportion. Then solve for m. 12 18 m 28 = 12 18 The extremes in the proportion == m 28 (Use a comma to separate answers as needed.) m= 12 18 The means in the proportion m 28 (Use a comma to separate answers as needed.) (Simplify your answer.) are = are
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Transcribed Image Text:Identify the means and extremes of the following proportion. Then solve for m.
12
18
m
28
=
12 18
The extremes in the proportion
==
m 28
(Use a comma to separate answers as needed.)
m=
12 18
The means in the proportion
m 28
(Use a comma to separate answers as needed.)
(Simplify your answer.)
are
=
are
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