The image displays two right triangles sharing a common side. ### Description: 1. **Larger Right Triangle:** - Hypotenuse: Not labeled - One leg is labeled as `h`. - The other leg (base) is labeled as `10`. 2. **Smaller Right Triangle (nested within the larger triangle):** - Hypotenuse: Labeled as `5`. - One leg is shared with the larger triangle and is a part of the hypotenuse of the larger triangle. - The other leg (base) is labeled as `6`. ### Analysis: - Both triangles have right angles indicating they are right triangles. - The base of the larger triangle is longer than that of the smaller triangle. - The smaller triangle's base and hypotenuse lengths suggest it is a scaled-down version of the larger triangle, indicating possible proportional relationship (similar triangles). This diagram could be used to teach concepts such as the Pythagorean theorem, similar triangles, or trigonometric ratios.
The image displays two right triangles sharing a common side. ### Description: 1. **Larger Right Triangle:** - Hypotenuse: Not labeled - One leg is labeled as `h`. - The other leg (base) is labeled as `10`. 2. **Smaller Right Triangle (nested within the larger triangle):** - Hypotenuse: Labeled as `5`. - One leg is shared with the larger triangle and is a part of the hypotenuse of the larger triangle. - The other leg (base) is labeled as `6`. ### Analysis: - Both triangles have right angles indicating they are right triangles. - The base of the larger triangle is longer than that of the smaller triangle. - The smaller triangle's base and hypotenuse lengths suggest it is a scaled-down version of the larger triangle, indicating possible proportional relationship (similar triangles). This diagram could be used to teach concepts such as the Pythagorean theorem, similar triangles, or trigonometric ratios.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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