½2 12-VTOG (5+81 √106. A~61.7737 6085 (b) Determine the perimeter of AABC to the nearest tenth. X √(8-1) ² + (-2-71² 172+-9² √106 +√√130 +12= 33.7 √99181 √130 7. Regular pentagon ABCDE is shown below. The distance from its center to any vertex is 8 centimeters. Point Soh Sah Toa F is located on AB such that FM is perpendicular to AB (a) Determine m/FMB. E (b) Determine the perimeter of ABCDE to the nearest tenth of a centimeter. (c) Determine the area of ABAM to the nearest square centimeter. +9² D M X F 8 cm C B

Q: (7.39 x 10-11)(5.42 x 10-13)

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