Gender 0.4 P(S=T) P(S=F) S P(B=T) P(B=F). T 0.7 F 0.001 0.999 Male 0.6 0.4 0.3 Smoking Female 0.2 0.8 P(C=T) P(C#F) Bronchitis Cancer 0.3 0.7 B F 0.1 0.9 Fatigue P(Fa=T) P(FaF) T. 0.9 0.1 Fa T. F 0.1 0.9 F T. 0.8 0.2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
M
0.6
Gender
0.4
G
P(S=T)
P(S=F)
S P(B=T) P(B=F)
Male
0.6
0.4
0.7
0.3
Smoking
Female
0.2
0.8
F 0.001 0.999
P(C=T) P(C#F)
Bronchitis
Cancer
0.3
0.7
B
F
0.1
0.9
P(Fa=T) P(Fa=F)
B
C
Fatigue
T.
0.9
0.1
Fa
T.
F
0.1
0.9
F
T.
0.8
0.2
F
0.1
0.9
i. Find probability of P(G, S, B, C, Fa), where Cancer = T, Smoking = F, Gender
Female, Bronchitis = T, Fatigue = T.
ii. Find probability of P(G, S, B, Fa), where Smoking = F, Gender = Female, Bronchitis
- T, Fatigue = T.
iii. Find the value of P(B).
Transcribed Image Text:M 0.6 Gender 0.4 G P(S=T) P(S=F) S P(B=T) P(B=F) Male 0.6 0.4 0.7 0.3 Smoking Female 0.2 0.8 F 0.001 0.999 P(C=T) P(C#F) Bronchitis Cancer 0.3 0.7 B F 0.1 0.9 P(Fa=T) P(Fa=F) B C Fatigue T. 0.9 0.1 Fa T. F 0.1 0.9 F T. 0.8 0.2 F 0.1 0.9 i. Find probability of P(G, S, B, C, Fa), where Cancer = T, Smoking = F, Gender Female, Bronchitis = T, Fatigue = T. ii. Find probability of P(G, S, B, Fa), where Smoking = F, Gender = Female, Bronchitis - T, Fatigue = T. iii. Find the value of P(B).
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