Homework Help is Here – Start Your Trial Now!
Science
Physics
Gaze into the Crystal Ball A set of coins is embedded in a spherical plastic paperweight having a radius of 5.0 cm. The index of refraction of the plastic is n, = 1.50. One coin is located 2.5 cm from the edge of the sphere (see the figure below). Find the position of the image of the coin. Light rays from a coin embedded in a plastic sphere form a virtual image between the surface of the object and the sphere surface. Because the object is inside the sphere, the front of the refracting surface is the interior of the sphere. d SOLUTION Conceptualize Because n, > n2, where n2 = 1.00 is the index of refraction for air , the rays originating from the coin in the figure are refracted away from the normal at the surface and diverge outward. Extending the outgoing rays backward shows an image point within the sphere. Categorize Because the light rays originate in one material and then pass through a curved surface into another material, this example involves an image formed by refraction Analyze (Use the following as necessary: n,, n2, P, 9, and R.) Apply n1 + "2 = "2 "1, noting from this table that R is negative: R n2 Substitute numerical values and solve for q (in cm): q = -1.7 |x cm Finalize The negative sign for q indicates that the image is in front of the surface; in other words, it is in the same medium as the object as shown in the figure. Therefore, the image must be virtual. The coin appears to be closer to the paperweight surface than it actually is.

Gaze into the Crystal Ball A set of coins is embedded in a spherical plastic paperweight having a radius of 5.0 cm. The index of refraction of the plastic is n, = 1.50. One coin is located 2.5 cm from the edge of the sphere (see the figure below). Find the position of the image of the coin. Light rays from a coin embedded in a plastic sphere form a virtual image between the surface of the object and the sphere surface. Because the object is inside the sphere, the front of the refracting surface is the interior of the sphere. d SOLUTION Conceptualize Because n, > n2, where n2 = 1.00 is the index of refraction for air , the rays originating from the coin in the figure are refracted away from the normal at the surface and diverge outward. Extending the outgoing rays backward shows an image point within the sphere. Categorize Because the light rays originate in one material and then pass through a curved surface into another material, this example involves an image formed by refraction Analyze (Use the following as necessary: n,, n2, P, 9, and R.) Apply n1 + "2 = "2 "1, noting from this table that R is negative: R n2 Substitute numerical values and solve for q (in cm): q = -1.7 |x cm Finalize The negative sign for q indicates that the image is in front of the surface; in other words, it is in the same medium as the object as shown in the figure. Therefore, the image must be virtual. The coin appears to be closer to the paperweight surface than it actually is.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
icon
Concept explainers
Question
Gaze into the Crystal Ball A set of coins is embedded in a spherical plastic paperweight having a radius of 5.0 cm. The index of refraction of the plastic is n, = 1.50. One coin is located 2.5 cm from the edge of the sphere (see the figure below). Find the position of the image of the coin. Light rays from a coin embedded in a plastic sphere form a virtual image between the surface of the object and the sphere surface. Because the object is inside the sphere, the front of the refracting surface is the interior of the sphere. d SOLUTION Conceptualize Because n, > n,, where n, = 1.00 is the index of refraction for air ,the rays originating from the coin in the figure are refracted away from the normal at the surface and diverge outward. Extending the outgoing rays backward shows an image point within the sphere. Categorize Because the light rays originate in one material and then pass through a curved surface into another material, this example involves an image formed by refraction Analyze (Use the following as necessary: n,, n2, p, q, and R.) n1 n. + n2 "1, noting from this table that R is negative: R Apply %3D n2 Substitute numerical values and solve for q (in cm): q = -1.7 X cm Finalize The negative sign for g indicates that the image is in front of the surface; in other words, it is in the same medium as the object as shown in the figure. Therefore, the image must be virtual. The coin appears to be closer to the paperweight surface than it actually is. EXERCISE A coin is embedded 1.89 cm from the surface of a similar ball of transparent substance having radius 3.4 cm and unknown composition. If the coin's image is virtual and located 1.44 cm from the surface, find the index of refraction of the substance. Hint n = Need Help? Read It Submit Answer
Transcribed Image Text:Gaze into the Crystal Ball A set of coins is embedded in a spherical plastic paperweight having a radius of 5.0 cm. The index of refraction of the plastic is n, = 1.50. One coin is located 2.5 cm from the edge of the sphere (see the figure below). Find the position of the image of the coin. Light rays from a coin embedded in a plastic sphere form a virtual image between the surface of the object and the sphere surface. Because the object is inside the sphere, the front of the refracting surface is the interior of the sphere. d SOLUTION Conceptualize Because n, > n,, where n, = 1.00 is the index of refraction for air ,the rays originating from the coin in the figure are refracted away from the normal at the surface and diverge outward. Extending the outgoing rays backward shows an image point within the sphere. Categorize Because the light rays originate in one material and then pass through a curved surface into another material, this example involves an image formed by refraction Analyze (Use the following as necessary: n,, n2, p, q, and R.) n1 n. + n2 "1, noting from this table that R is negative: R Apply %3D n2 Substitute numerical values and solve for q (in cm): q = -1.7 X cm Finalize The negative sign for g indicates that the image is in front of the surface; in other words, it is in the same medium as the object as shown in the figure. Therefore, the image must be virtual. The coin appears to be closer to the paperweight surface than it actually is. EXERCISE A coin is embedded 1.89 cm from the surface of a similar ball of transparent substance having radius 3.4 cm and unknown composition. If the coin's image is virtual and located 1.44 cm from the surface, find the index of refraction of the substance. Hint n = Need Help? Read It Submit Answer
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Refraction of light
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS