Gaseous water and solid calcium oxide are produced by the decomposition of solid calcium hydroxide. Write a balanced chemical equation for this reaction. 0-0 X

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Educational Content:**

**Chemical Reaction Decomposition**

In this exercise, we are asked to write a balanced chemical equation for the decomposition of solid calcium hydroxide, which produces gaseous water and solid calcium oxide.

**Chemical Reaction:**

To decompose solid calcium hydroxide (Ca(OH)₂), the balanced chemical equation is:

\[ \text{Ca(OH)}_2(s) \rightarrow \text{CaO}(s) + \text{H}_2\text{O}(g) \]

**Explanation:**

- **Reactant:** Calcium hydroxide (Ca(OH)₂) in solid form.
- **Products:** 
  - Calcium oxide (CaO) in solid form.
  - Water (H₂O) in gaseous form.

This equation demonstrates the breakdown of the compound calcium hydroxide into its constituent oxide and water molecules. Balancing this equation ensures that the number of atoms for each element is equal on both sides of the equation, adhering to the law of conservation of mass.
Transcribed Image Text:**Educational Content:** **Chemical Reaction Decomposition** In this exercise, we are asked to write a balanced chemical equation for the decomposition of solid calcium hydroxide, which produces gaseous water and solid calcium oxide. **Chemical Reaction:** To decompose solid calcium hydroxide (Ca(OH)₂), the balanced chemical equation is: \[ \text{Ca(OH)}_2(s) \rightarrow \text{CaO}(s) + \text{H}_2\text{O}(g) \] **Explanation:** - **Reactant:** Calcium hydroxide (Ca(OH)₂) in solid form. - **Products:** - Calcium oxide (CaO) in solid form. - Water (H₂O) in gaseous form. This equation demonstrates the breakdown of the compound calcium hydroxide into its constituent oxide and water molecules. Balancing this equation ensures that the number of atoms for each element is equal on both sides of the equation, adhering to the law of conservation of mass.
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