g=9.81 ms ² G= 6.673 × 10-¹¹ N m² kg2 1 AU = 1.50 × 108 km 1. A potter's wheel of mass 10 kg and radius 30 cm radius can be modelled as a uniform disk (a) The wheel is spun up from rest to 100 revolutions per minute in a time of 20 seconds What was the angular acceleration of the wheel? You may assume the wheel rotates in an anti-clockwise sense. (b) The potter now places a lump of clay onto the centre of the wheel. The clay has a mas 2 kg and is in the shape of a solid cylinder of radius 4 cm. The length of the cylinder i parallel with the rotational axis of the potter's wheel. Calculate the new momentum o inertia of the system, which is the sum of the momentum of inertia of the wheel and th the momentum of inertia of the clay, and use this to determine the new angular speed of the wheel and clay system. (c) The potter now applies a constant force of 2 N tangentially to the wheel opposite the direction of its spin. What is the new angular acceleration of the wheel and clay system (d) If the potter applies this force for a time of 2 seconds, what is the resulting angula speed of the wheel?

g=9.81 ms ² G= 6.673 × 10-¹¹ N m² kg2 1 AU = 1.50 × 108 km 1. A potter's wheel of mass 10 kg and radius 30 cm radius can be modelled as a uniform disk (a) The wheel is spun up from rest to 100 revolutions per minute in a time of 20 seconds What was the angular acceleration of the wheel? You may assume the wheel rotates in an anti-clockwise sense. (b) The potter now places a lump of clay onto the centre of the wheel. The clay has a mas 2 kg and is in the shape of a solid cylinder of radius 4 cm. The length of the cylinder i parallel with the rotational axis of the potter's wheel. Calculate the new momentum o inertia of the system, which is the sum of the momentum of inertia of the wheel and th the momentum of inertia of the clay, and use this to determine the new angular speed of the wheel and clay system. (c) The potter now applies a constant force of 2 N tangentially to the wheel opposite the direction of its spin. What is the new angular acceleration of the wheel and clay system (d) If the potter applies this force for a time of 2 seconds, what is the resulting angula speed of the wheel?

Name: Do part b,c,d g = 9.81 ms-2 G = 6.673 × 10-1" N m² kg² 1 AU = 1.50 x 1
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Description: Do part b,c,d g = 9.81 ms-2 G = 6.673 × 10-1" N m² kg² 1 AU = 1.50 x 10° km1. A potter's wheel of mass 10 kg and radius 30 cm radius can be modelled as a uniform disk.(a) The wheel is spun up from rest to 100 revolutions per minute in a time of 20 se

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

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Concept explainers

Simple harmonic motion

Simple harmonic motion is a type of periodic motion in which an object undergoes oscillatory motion. The restoring force exerted by the object exhibiting SHM is proportional to the displacement from the equilibrium position. The force is directed towards the mean position. We see many examples of SHM around us, common ones are the motion of a pendulum, spring and vibration of strings in musical instruments, and so on.

Simple Pendulum

A simple pendulum comprises a heavy mass (called bob) attached to one end of the weightless and flexible string.

Oscillation

In Physics, oscillation means a repetitive motion that happens in a variation with respect to time. There is usually a central value, where the object would be at rest. Additionally, there are two or more positions between which the repetitive motion takes place. In mathematics, oscillations can also be described as vibrations. The most common examples of oscillation that is seen in daily lives include the alternating current (AC) or the motion of a moving pendulum.

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Do part b,c,d

g = 9.81 ms-2 G = 6.673 × 10-1" N m² kg² 1 AU = 1.50 x 10° km
1. A potter's wheel of mass 10 kg and radius 30 cm radius can be modelled as a uniform disk.
(a) The wheel is spun up from rest to 100 revolutions per minute in a time of 20 seconds.
What was the angular acceleration of the wheel? You may assume the wheel rotates in
an anti-clockwise sense.
(b) The potter now places a lump of clay onto the centre of the wheel. The clay has a mass
2 kg and is in the shape of a solid cylinder of radius 4 cm. The length of the cylinder is
parallel with the rotational axis of the potter's wheel. Calculate the new momentum of
inertia of the system, which is the sum of the momentum of inertia of the wheel and the
the momentum of inertia of the clay, and use this to determine the new angular speed
of the wheel and clay system.
(c) The potter now applies a constant force of 2 N tangentially to the wheel opposite the
direction of its spin. What is the new angular acceleration of the wheel and clay system?
(d) If the potter applies this force for a time of 2 seconds, what is the resulting angular
speed of the wheel?

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