г. у = эу! 3 X+l 3 y² = (x+₁).0 - 3 [1] (x+1)² ) - X - 3 (x+1)² + (x-1)0-3[1] (x-1)² (Aus) 3 (x-1)²

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.9: Dividing Real Numbers
Problem 10MRE
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can you explain how they got the highlighted line in simple terms

2.
so
}}
3
Xtl
, hе
y² = (x+₁).0-3[1]
(x+1)²
3
X-1
3
(x+1)²
-
+
(x-1)0-3[1]
(x-1)²
3
(x-1)² (Aus)
Transcribed Image Text:2. so }} 3 Xtl , hе y² = (x+₁).0-3[1] (x+1)² 3 X-1 3 (x+1)² - + (x-1)0-3[1] (x-1)² 3 (x-1)² (Aus)
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