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G. The voltage V in a simple electrical circuit is slowly decreasing as a battery wears out. The Resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing with respect to time at the instant when R = dV/dt = -0.01V/s, and dR/dt = 0.032/s. (Answ: -3.1 x 10-A/s) 4002, I = 0.08A,

G. The voltage V in a simple electrical circuit is slowly decreasing as a battery wears out. The Resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing with respect to time at the instant when R = dV/dt = -0.01V/s, and dR/dt = 0.032/s. (Answ: -3.1 x 10-A/s) 4002, I = 0.08A,

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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G. The voltage V in a simple electrical circuit is slowly decreasing as a battery wears out. The Resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing with respect to time at the instant when R = dV/dt = –0.01V/s, and dR/dt= 4002, I = 0.08A, 0.032/s. (Answ: -3.1 x 10-A/s)
Transcribed Image Text:G. The voltage V in a simple electrical circuit is slowly decreasing as a battery wears out. The Resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing with respect to time at the instant when R = dV/dt = –0.01V/s, and dR/dt= 4002, I = 0.08A, 0.032/s. (Answ: -3.1 x 10-A/s)
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