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G. 620mm 1.8m 1.2m

G. 620mm 1.8m 1.2m

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The figure represents a front wheel-drive vehicle with a total mass of 1650 kg. Analyze the equilibrium of forces and moments and answer the questions. 620mm 1.8m 1.2m Fig. Front-Wheel-Drive The normal reactions on both set of wheels when the vehicle is at rest on a horizontal road surface are: Nfo = N on front wheels and Nro = N on rear wheels Analyze, with the a proper force diagram and make your determination: the vehicle needs to at a rate of mls2 to achieve equal equal normal forces on both set of rear and front wheel. During the sudden change of speed (acceleration or deceleration, depending on the results informed by your calculation), reactions are respectively N1 = N on rear wheels and NI = N on front wheels. If the same front-wheel-drive vehicle is driven so as to maintain a constant speed up a gradient of 14%, the normal reactions on the the wheel as the vehicle moves up the incline, are respectively, N, = N on rear wheels and Nf. N on front wheels resulting into %3D ratios r, = NrolN and rf = Nfo/Nf. The ratios suggest that * load in the front suspension and load in the rear suspension in comparison to respective nominal loads measured on a horizontal road surface. Note: a gradient of 14% means tane = 10/100 = 0.1 where 0 is the angle of
Transcribed Image Text:The figure represents a front wheel-drive vehicle with a total mass of 1650 kg. Analyze the equilibrium of forces and moments and answer the questions. 620mm 1.8m 1.2m Fig. Front-Wheel-Drive The normal reactions on both set of wheels when the vehicle is at rest on a horizontal road surface are: Nfo = N on front wheels and Nro = N on rear wheels Analyze, with the a proper force diagram and make your determination: the vehicle needs to at a rate of mls2 to achieve equal equal normal forces on both set of rear and front wheel. During the sudden change of speed (acceleration or deceleration, depending on the results informed by your calculation), reactions are respectively N1 = N on rear wheels and NI = N on front wheels. If the same front-wheel-drive vehicle is driven so as to maintain a constant speed up a gradient of 14%, the normal reactions on the the wheel as the vehicle moves up the incline, are respectively, N, = N on rear wheels and Nf. N on front wheels resulting into %3D ratios r, = NrolN and rf = Nfo/Nf. The ratios suggest that * load in the front suspension and load in the rear suspension in comparison to respective nominal loads measured on a horizontal road surface. Note: a gradient of 14% means tane = 10/100 = 0.1 where 0 is the angle of
In a SHM (Simple Harmonic Motion), a point in horizontal motion passes a fixed point A of coordinates x, and point B of coordinates x, with the same speed. If AB = that it takes Ata-b 300mm, assuming that point A is at the left of point B, and = 3sec to move from A to B and Atp-b 4sec to move outward and then back to B. Analyze the SHM and then calculate: 1. The frequency: • and period of the motion 2. Calculate the amplitude of the SHM motion 3. The equation of motion is x(t) = cos( %3D t + p.) [mm] 4. The magnitude of the speed at A, is vA = m/s and the acceleration at B is a p = m/s-2
Transcribed Image Text:In a SHM (Simple Harmonic Motion), a point in horizontal motion passes a fixed point A of coordinates x, and point B of coordinates x, with the same speed. If AB = that it takes Ata-b 300mm, assuming that point A is at the left of point B, and = 3sec to move from A to B and Atp-b 4sec to move outward and then back to B. Analyze the SHM and then calculate: 1. The frequency: • and period of the motion 2. Calculate the amplitude of the SHM motion 3. The equation of motion is x(t) = cos( %3D t + p.) [mm] 4. The magnitude of the speed at A, is vA = m/s and the acceleration at B is a p = m/s-2
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