The given signal is expressed as:\[ g(t) = 9 \text{rect} \left(\frac{t}{3}\right) \]Using the integration property, the Continuous-Time Fourier Transform (CTFT) of the given signal is:\[ g(t) \xleftrightarrow{\mathcal{F}} A \text{sinc} (Bf) \]The numerical values of the constants are \( A = \underline{\hspace{1cm}} \) and \( B = \underline{\hspace{1cm}} \).

In this question we will find Fourier transform of given signal....

Answered: g (t) 9rect () Using the integration…

g (t) 9rect () Using the integration property, the CTFT of the given signal is g (t) 4 Asinc (Bf) The numerical values of the constants are A= | and B=

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

The given signal is expressed as:

\[ g(t) = 9 \text{rect} \left(\frac{t}{3}\right) \]

Using the integration property, the Continuous-Time Fourier Transform (CTFT) of the given signal is:

\[ g(t) \xleftrightarrow{\mathcal{F}} A \text{sinc} (Bf) \]

The numerical values of the constants are \( A = \underline{\hspace{1cm}} \) and \( B = \underline{\hspace{1cm}} \).

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