**Equilibrium Constants and Reversed Reactions**When considering chemical equilibrium, it's important to understand how equilibrium constants change when reactions are reversed. Let's examine a practical example:**Given Reaction:**\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]- Equilibrium constant (\(K_p\)) = 1.84 at a specific temperature.**Question:**What is the value of \(K_p\) for the reversed reaction at the same temperature?\[ \text{PCl}_3(g) + \text{Cl}_2(g) \rightleftharpoons \text{PCl}_5(g) \]**Answer:**For a reaction that is reversed, the equilibrium constant is the reciprocal of the original equilibrium constant.**Calculation:**\[ K_p(\text{reversed}) = \frac{1}{K_p(\text{original})} = \frac{1}{1.84} \approx 0.5435 \]Thus, the \(K_p\) for the reaction \(\text{PCl}_3(g) + \text{Cl}_2(g) \rightleftharpoons \text{PCl}_5(g)\) is approximately 0.5435 at the same temperature.

The value of Kp for second reaction are as follows.

Answered: (g) → PCI3(g) + Cl2(g) has Kp = 1.84 at…

(g) → PCI3(g) + Cl2(g) has Kp = 1.84 at a given temperature. What is the value p for the reaction PCI3(g) + Cl2(g)<>PCI5(g) at the same temperature? 1.84

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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