g) Determine the product of Factorial of 5 and Fibonacci of 5 using the recursive function as follows: Factorial: n!-nx(n-1)×(n-2)×...×2×1, n 21 Fibonacci: fn = fn-1+ fn-2i n2 3; f = f= 1 %3D

Q: FACTORIAL The number of different ways to arrange n objects is given by n!= nx (n-1)x(n-2)x...x3x2x1…

A: Given: The number of different ways to arrange n objects is given by  n! = n×n-1×n-2×...×3×2×1

Q: P (A) a, P (B) b and P (P (AB)- c then the expression of P (A'B')in erms of a, b and c is:

A:

Q: (n^2-n)+((n-1)^2-(n-1))+....+(1^2-1) =n(n+1)(2n+1)/6 - n(n+1)/2

A: We shall first derive the formulas for sum of first n natural numbers and sum of squares of first n…

Q: Find each (n+3)(n+2) (4n 5)(3n + 2) (n+7)(n + 5)

A: Since you have posted multiple subparts we solve the first three subparts for you to get the…

Q: Find the fourth term m the papansion of

A: 1-23x36 use the binomial theorem a+bn=∑i=0nnian-ibi 1-2x336=∑i=066i· 16-i-2x33i

Q: How many 6-digit numbers have three even and three odd digits? (The first digit cannot be zero.)

A: It is given that a 6-digit number is to be formed which will have three even and three odd digits.…

Q: This will be (n+k-1)= 29+6-1 29 -¹1) = 34 29 = 278, 256.

A:

Q: Malik currently has 39 tulips in his yard. Each year he plants 3 more. (a) Which of the following is…

A: given data  malik havs 39 tulips in his yard each year he plants 3 more  so,  p0= 39 d = 3

Q: Let x≤y≤z be natural numbers. Prove the attached picture by (a) showing that both sides are…

A: (a). zyyx=z!y!·(z-y)!×y!x!·(y-x)!               =z!x!(z-x)!·(z-x)!(z-y)!·(y-x)!…

Q: Use the binomial theorem to show that 72 Σ(1) ( **(?). i-0 0.

A: Use binomial theorem to show that given formula.

Q: If n is prime, then 2" – 1 is prime.

A:

Q: Prove the property of the Fibonacci numbers, F(n) = 5(n 4) + 3F(n-5), for n ≥6

A: We have to prove the property of the given Fibonacci numbers F(n) = 5F(n-4) + 3F(n-5) ,  for n≥6

Q: Find a formula for the general term a, {5, 8, 11, 14, 17, .} 5n + 3 On+3 O 3n + 2 O 2n + 3

A: We can answer the question as below

Q: How many zeroes does 188! end with?

A: count number of five's in 188, 5*2=10 . Divide 188 and write quotient again divide quotient again by…