g Assume that the sample is a simple random sample. less ldn 7 25 6.5 13.5 20.5 12 11.5 8 21 18 uming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. Ho = 16 ug/g H p>16 ug/g O B. Ho u> 16 ug/g H, p< 16 ug/g C. Ho H=16 ug/g HH<16 ug/g OD. Ho: = 16 ug/g H, p 16 ug/g

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Chapter10: Statistics
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**Educational Website Text Transcription**

Title: Hypothesis Testing of Lead Concentration in Traditional Medicines

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Listed below are the lead concentrations in µg/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 µg/g. Assume that the sample is a simple random sample.

Data: 7, 2.5, 6.5, 13.5, 20.5, 12, 11.5, 8, 21, 18

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**Question:**

Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?

- **Option A:**
  - \( H_0: \mu = 16 \, \text{µg/g} \)
  - \( H_1: \mu > 16 \, \text{µg/g} \)

- **Option B:**
  - \( H_0: \mu > 16 \, \text{µg/g} \)
  - \( H_1: \mu < 16 \, \text{µg/g} \)

- **Option C:**
  - \( H_0: \mu = 16 \, \text{µg/g} \)
  - \( H_1: \mu < 16 \, \text{µg/g} \)

- **Option D:**
  - \( H_0: \mu = 16 \, \text{µg/g} \)
  - \( H_1: \mu \neq 16 \, \text{µg/g} \)

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In this context, the correct hypothesis pair should reflect the initial claim that the mean lead concentration is less than 16 µg/g.
Transcribed Image Text:**Educational Website Text Transcription** Title: Hypothesis Testing of Lead Concentration in Traditional Medicines --- Listed below are the lead concentrations in µg/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 µg/g. Assume that the sample is a simple random sample. Data: 7, 2.5, 6.5, 13.5, 20.5, 12, 11.5, 8, 21, 18 --- **Question:** Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? - **Option A:** - \( H_0: \mu = 16 \, \text{µg/g} \) - \( H_1: \mu > 16 \, \text{µg/g} \) - **Option B:** - \( H_0: \mu > 16 \, \text{µg/g} \) - \( H_1: \mu < 16 \, \text{µg/g} \) - **Option C:** - \( H_0: \mu = 16 \, \text{µg/g} \) - \( H_1: \mu < 16 \, \text{µg/g} \) - **Option D:** - \( H_0: \mu = 16 \, \text{µg/g} \) - \( H_1: \mu \neq 16 \, \text{µg/g} \) --- In this context, the correct hypothesis pair should reflect the initial claim that the mean lead concentration is less than 16 µg/g.
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