G = 2 kN 20° F = 4 kN 40° 30° 40° H= 3 kN K = 5 kN

Q: Determine the minimum magnitude of F for which motion impends if µg = 0.3 а 58.9N c F>0 %3D b 6.00 N…

A: Calculating the minimum magnitude F: F¯=μsNF∵NF=mg=20×9.81=196.2 NF¯=0.3×196.2F¯=58.86 N≃58.9 N

Q: Situation 1. From the figure no 1, point A is supported by a hinged while C and D are supported by a…

A: Given: Required: Reaction at support C, D and A

Q: 100 kN w = 40KN/m C 5m Зт р 3m А 8m OB 10т THREE MOMENT EQUATION METHOD 5) What is the bending…

A:

Q: 3/17 4 m 8, 30 Y--- x 300x9.81 N A

A:

Q: m 135 KN 44 kN/m t 22 kN/m 5m

A: Given Load = 135 kN UDL = 22 KN/m UVL = 44 KN/m

Q: 1- The disk is moving to the left such that it has an angular acceleration a = 8 rad/s and angular…

A:

Q: Problem 2.4 Find the angle '0' between force vectors F. and Fa F800 N VIỆT HIỆN NHIỆT HIỆN THỦ TH…

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Q: 6 m B 6 m 40 kN 40 kN 4@ 6m

A:

Q: 03 Figure 03 shows an overhead crane truss supported by pin and roller supports at point A and E.…

A:

Q: 3 m 30 KN/m 6 m 3 m

A: The modulus of elasticity is,the moment of inertia is,to determine:the maximum deflection of the…

Q: 3: Determine the magnitude of the Maximum shear force in the beam Vmax = 7.5 kNO Vmax = 50 kNO Vmax…

A:

Q: Q.5: Locate the maximum Moment at a distance X from the support A Maximum moment at X= 2.0 m O…

A: Given data  UDL Span length  Overhanging beam

Q: 264 kN 264 kN 264 kN 264 kN Η 54 kN B. C 3.00 m 3.00 m 3.00 m 3.00 m 4.00 m

A:

Q: H 4 kN I 60° D E F G A C B mim 2 m 2 m

A: Explanation of above answers are :

Q: Construct the influence lines for the member force of AB, BG, and CD. Load moves along AE.

A:

Q: 10 kN 80 kN/m В A D 4 m 1 m'1m

A:

Q: Determine the deflection @ Cusing Moment Area Method. (Your final answer should be in "mm")

A:

Q: 1. For the column shown below, create an interaction diagram on Excel for bending about the strong…

A:

Q: Determine the maximum height, h, perpendicular to the ground. h 55.30 ft/s² 25° 35°

A:

Q: MA "(A RA 20 KN 20 KN MB KAB = 10.67x10⁹ -3 m3 m3 m4 m RB 60 KN KBC=9x10⁹ 4 m- a. Construct the…

A: Given: Required : Moment distribution table Moments Reaction

Q: Refer to the beam shown, 75 kN/m 2m For the beam shown, what is the value of 084 in terms of El…

A:

Q: 1 m 1 0.8 m B 4 kN 2 m 4 m 1.4 m C P D 4 kN 3 m 2 m E

A: Given data  Find y value at D.

Q: e beam loaded as shown and the Equations of the SPa, 1= 75 x 10 mm 2 kN/m 1.8 m B 3m →→x1 M(x) =…

A:

Q: 4. Given f = 0.008, determine energy lost and Pressure drop between points 1 and 2 [307.7 J/kg,…

A: As per our guidelines we are supposed to answer first question only. So please repost others as…

Q: 50 kN 10 kN/m D BA 5 m 5 m 5 m 5 m

A:

Q: Calculate the sag, relative to A, of the points C and D in the cable shown in Fig. P.5.3. Determine…

A: It is required to find:- Sag at C & D with respect to A And tension in cable segments AB, BC, CD…

Q: Problem #2 50 kN 15 kN/m 90 kN El = constant E=70 GPa 1-95x10° mm Required: 8, dc Og A + -6 m - 9 m…

A: Given simply support beam with overhang E = 70 GPa I = 95 * 10^6 mm4 Calculate reaction at B by…

Q: Solve the following and provide complete solution for verification: (Round off answers in…

A:

Q: M M M 13.9kft СЕ 4.64 kips M 9º MB 30 kips KN KN E E ·6² 6². 17.97kips 40kips E kNm kNm kNm 4…

A: Given data:- Below diagram is given in question;

Q: Find degree of static indeterminacy

A:

Q: What is the moment value at the free-end in KN-m? O +222.01 KN-m O + 216.09 KN-m O- 10 KN-m O + 216…

A: Option (C) is the correct answer.

Q: The beam is subjected to the loading shown. If a = 180 mm, determine the absolute maximum bending…

A: Absolute Max Stress = 105.105 MPaExplanation:

Q: 6' 8⁰ I 10' 5' с 1000 155 A 45° F 2000 15's 61 J S D B Calculate Forces in 7' 500 lbs IJ FD CB H 45°…

A:

Q: BC, CH, HI, and CI. (Ans: load @ H: NBC = -1.78, P16.45 NCH = 0.56) %3D A E H. -16 ft 16 ft 16 ft16…

A: ASKED: To compute the force in members BC, CH, HI and CI.   Given, load is placed at H.

Q: X₁ = 22.79+ |X₂= 60-x₁ 37-21 Z am AV 22-79 X) 37.21 1X ₂ 50 kN/m 60 o 3 15m BY B BH LOWEST POINT…

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Q: 60 kN/m 60 kN/m R1 R2 3 m 2 m 3 m

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Q: 45 KN/m 200 50 KN A 9.00 m RB 3.50 m 150 KN-m

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Q: Using Slope Deflection Method for Figure 03 and Figure 04, determine MAB, MBA, MBC, MCB, MCD, MDC

A: Given- b1 = 6.45m h1 = o.55m b2 = 035m h2 = 0.6m  b3 = 0.4m h3 = 0.65mE= 2.1×107kpaw=1290kn/m To…

Design of structures using FEA

An arrangement, in which various members are interconnected with their constrained relative motion, the whole arrangement is then known as a structure. The degree of freedom of such a structure is zero. In such a structure, the load can act throughout the length of the structure or at the joints.