f(x)dx =F(b)- F(a) Please explein in detar L, . To evaluate the integral, first find F(s).) How to get from A to B Let f(s) = 1+s F(s)=s-2s 1/2+C lue of E/h) Ela) Thus there is no need to

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please explain in detail, how to get from A to B.
s2+V5
ds.
Evaluate the integral
1
o leps i vb
Begin by simplifying the integrand of
s2
-ds and expressing it in exponential form.
According to the second part of the fundamental theorem of calculus, if f is continuous at every point of [a,b] and F is any
antiderivative of f on [a,b], then the definite integral can be evaluated using the following formula.
b.
rox)dx = F(b)- F(a)
Please explan in deta, L,
2. To evaluate the integral, first find F(s).) How to get from A to B
Let f(s) = 1+s3/2
to
F(s) =s-2s 1/2 +C
Because of the subtraction, a constant in F(x) will not affect the value of F(b) - F(a). Thus, there is no need to include the
constant C.
+ V5
-ds
= F(V6) - F(1)
%3D
Next, simplify F(V6).
F(V6)
(V6) - 2. (V6)
(V6) - 2. (61/2) -1/2
= (V6) -2.6-1/4
-1/2
2
= y6 -
Simplify F(1).
F(1) = (1)-2-(1)-1/2
= -1
Finally, evaluate the integral.
Transcribed Image Text:s2+V5 ds. Evaluate the integral 1 o leps i vb Begin by simplifying the integrand of s2 -ds and expressing it in exponential form. According to the second part of the fundamental theorem of calculus, if f is continuous at every point of [a,b] and F is any antiderivative of f on [a,b], then the definite integral can be evaluated using the following formula. b. rox)dx = F(b)- F(a) Please explan in deta, L, 2. To evaluate the integral, first find F(s).) How to get from A to B Let f(s) = 1+s3/2 to F(s) =s-2s 1/2 +C Because of the subtraction, a constant in F(x) will not affect the value of F(b) - F(a). Thus, there is no need to include the constant C. + V5 -ds = F(V6) - F(1) %3D Next, simplify F(V6). F(V6) (V6) - 2. (V6) (V6) - 2. (61/2) -1/2 = (V6) -2.6-1/4 -1/2 2 = y6 - Simplify F(1). F(1) = (1)-2-(1)-1/2 = -1 Finally, evaluate the integral.
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