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f(x, y) = V(x² + y²)² 3 2

f(x, y) = V(x² + y²)² 3 2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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the function  "first image" is defined in R^2, so we can say that fx(x,y) equals to


choose an option: "second image"

if (x, y) + (0,0) 3V1² + Y² 0, a. if (1, y) = (0, 0) if (x, y) + (0,0) O b. { 3V2 +Y² if (x, y) = (0,0) 0, C. 3V7² + Y² _for all (x, y) in R?. d. 3V1² + Y² _for all (x, y) in R².
Transcribed Image Text:if (x, y) + (0,0) 3V1² + Y² 0, a. if (1, y) = (0, 0) if (x, y) + (0,0) O b. { 3V2 +Y² if (x, y) = (0,0) 0, C. 3V7² + Y² _for all (x, y) in R?. d. 3V1² + Y² _for all (x, y) in R².
f(x, y) = V[x² + y?)² 3
Transcribed Image Text:f(x, y) = V[x² + y?)² 3
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