f(x, y) = 30 for r = 0, 1,2, 3; y = 0, 1, 2, %3D Find: (a) P(X < 2, Y = 1); (b) P(X > 2, Y< 1); (c) P(X>Y ); (d) P(X+ Y = 4). 2. From a sack of fruit containing 3 oranges, 2 apples, and 3 bananas, a random sample of pieces of fruit is selected. If X is the number of oranges and Y is the number of apples in th sample, find: (a) the joint probability distribution of X and Y ; (b) P[(X, Y ) E A], where A the region that is given by {(x, y) | x + y < 2}.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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HELP WITH NUMBER TWO, WITH COMPLETE SOLUTION AND GRAPH THANK YOUU, PLEASE DON'T MAKE IT COMPLICATED.

1. If the joint probability is given by:
x + y
f(x, y)
for x = 0, 1,2, 3; y = 0, 1,2,
%3D
30
Find:
(a) P(X < 2, Y = 1);
(b) P(X > 2, Y < 1);
(c) P(X>Y );
(d) P(X + Y = 4).
2. From a sack of fruit containing 3 oranges, 2 apples, and 3 bananas, a random sample of 4
pieces of fruit is selected. If X is the number of oranges and Y is the number of apples in the
sample, find:
(a) the joint probability distribution of X and Y ;
(b) P[(X, Y ) E A], where A is the region that is given by {(x, y) | x + y < 2}.
Transcribed Image Text:1. If the joint probability is given by: x + y f(x, y) for x = 0, 1,2, 3; y = 0, 1,2, %3D 30 Find: (a) P(X < 2, Y = 1); (b) P(X > 2, Y < 1); (c) P(X>Y ); (d) P(X + Y = 4). 2. From a sack of fruit containing 3 oranges, 2 apples, and 3 bananas, a random sample of 4 pieces of fruit is selected. If X is the number of oranges and Y is the number of apples in the sample, find: (a) the joint probability distribution of X and Y ; (b) P[(X, Y ) E A], where A is the region that is given by {(x, y) | x + y < 2}.
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